Problem 33
Question
Calculate pH of \(0.02 \mathrm{M}-\) HA solution. \(K_{\mathrm{a}}\) for \(\mathrm{HA}=2 \times 10^{-12} .(\log 2=0.3\) \(\log 3=0.48\) ) (a) \(6.65\) (b) \(6.70\) (c) \(6.85\) (d) \(6.52\)
Step-by-Step Solution
Verified Answer
6.70
1Step 1: Understanding pH and Acid Dissociation
The pH of a solution is a measure of its acidity or basicity. For a weak acid HA dissociating as HA → H+ + A-, the pH is related to the acid dissociation constant (Ka) and the concentration of the acid ([HA]). The relevant equation for a weak mono-protic acid is: Ka = [H+][A-]/[HA].
2Step 2: Set Up the Equilibrium Equation
Assume that the acid dissociates partially, and x is the concentration of H+ and A- at equilibrium. Since the dissociation is a 1:1 ratio, [H+] = [A-] = x and [HA] will become 0.02 - x. However, as Ka is very small, x will be very small compared to 0.02, thus we can approximate [HA] as 0.02 M. The equilibrium equation is Ka = (x)(x)/(0.02).
3Step 3: Solve for x
Plug in the value of Ka into the equilibrium equation to find x (the concentration of H+). Ka = (2 x 10^-12) = (x)(x)/(0.02). By solving this equation, x^2 = (2 x 10^-12)(0.02). Thus, x^2 = 4 x 10^-14 and x = 2 x 10^-7 M.
4Step 4: Calculate the pH
The pH of the solution is -log[H+]. Substitute x into this equation: pH = -log(2 x 10^-7).
5Step 5: Simplify the pH Calculation
By using logarithm properties: pH = -log(2) - log(10^-7) = -0.3 + 7 = 6.7.
Key Concepts
Acid Dissociation ConstantEquilibrium ConstantpH of SolutionLogarithm Properties
Acid Dissociation Constant
Understanding how a weak acid dissociates in water is crucial to calculating the pH of its solution. The acid dissociation constant, often represented as Ka, measures the strength of an acid in solution. It indicates the equilibrium between the undissociated acid (HA) and the ions it forms, commonly H+ and A-. For the equation HA ↔ H+ + A-, the Ka is expressed mathematically as:
\( K_a = \frac{[H^+][A^-]}{[HA]} \).
This equation implies that the higher the Ka, the stronger the acid because it dissociates more in water. Conversely, a smaller Ka value signifies a weaker acid. In our case, with a Ka of \(2 \times 10^{-12}\), HA can be classified as a weak acid, indicating it only partially dissociates in solution.
\( K_a = \frac{[H^+][A^-]}{[HA]} \).
This equation implies that the higher the Ka, the stronger the acid because it dissociates more in water. Conversely, a smaller Ka value signifies a weaker acid. In our case, with a Ka of \(2 \times 10^{-12}\), HA can be classified as a weak acid, indicating it only partially dissociates in solution.
Equilibrium Constant
The equilibrium constant, in the context of acid-base reactions, is indeed the acid dissociation constant Ka. At equilibrium, the rate of the forward reaction (the dissociation of the weak acid) equals the rate of the reverse reaction (the recombination of the ions to form the weak acid). This condition is captured by the equilibrium expression.
Since the dissociation of a weak acid is a dynamic process, the concept of equilibrium allows us to calculate the exact concentrations of all species in solution at any given time, provided we know the initial concentration of the acid and the Ka value. It's important to note that in dilute solutions, where the acid dissociation is very small (Ka << 1), we often make the assumption that the initial concentration of the acid remains relatively unchanged, thus simplifying our calculations greatly.
Since the dissociation of a weak acid is a dynamic process, the concept of equilibrium allows us to calculate the exact concentrations of all species in solution at any given time, provided we know the initial concentration of the acid and the Ka value. It's important to note that in dilute solutions, where the acid dissociation is very small (Ka << 1), we often make the assumption that the initial concentration of the acid remains relatively unchanged, thus simplifying our calculations greatly.
pH of Solution
The pH of a solution quantifies its acidity or basicity on a logarithmic scale with values typically ranging from 0 to 14. A pH lower than 7 indicates an acidic solution, while a pH higher than 7 indicates a basic (or alkaline) solution, with 7 being neutral pH.
To calculate the pH of a weak acid solution, we first ascertain the concentration of hydrogen ions ([H+]) in the solution at equilibrium. As we saw in the exercise, once we have the H+ concentration, we apply the formula:
\( pH = -\log [H^+] \).
The 'p' in pH stands for 'potenz', which means power in German, and the H is for hydrogen. Therefore, pH is essentially telling us the 'power' or concentration of hydrogen ions present in a solution. The lower the concentration of H+ (i.e., the higher the pH), the less acidic the solution is, and vice versa.
To calculate the pH of a weak acid solution, we first ascertain the concentration of hydrogen ions ([H+]) in the solution at equilibrium. As we saw in the exercise, once we have the H+ concentration, we apply the formula:
\( pH = -\log [H^+] \).
The 'p' in pH stands for 'potenz', which means power in German, and the H is for hydrogen. Therefore, pH is essentially telling us the 'power' or concentration of hydrogen ions present in a solution. The lower the concentration of H+ (i.e., the higher the pH), the less acidic the solution is, and vice versa.
Logarithm Properties
Essential to pH calculations are properties of logarithms, which are the mathematical tools used to transform the multiplication and division of numbers into addition and subtraction problems, easing the process of calculation. Logarithms have several properties that are commonly used:
Using these properties simplifies the pH calculation process substantially. For instance, we utilized the fact that \(\log(10^{-7}) = -7\) and therefore were able to calculate the pH by subtracting this value from the logarithm of the concentration of H+ ions.
- The product rule: \(\log(a \cdot b) = \log(a) + \log(b)\)
- The quotient rule: \(\log(\frac{a}{b}) = \log(a) - \log(b)\)
- The power rule: \(\log(a^b) = b \cdot \log(a)\)
- If log base 10 is used (as in pH calculations), \(\log(10) = 1\).
Using these properties simplifies the pH calculation process substantially. For instance, we utilized the fact that \(\log(10^{-7}) = -7\) and therefore were able to calculate the pH by subtracting this value from the logarithm of the concentration of H+ ions.
Other exercises in this chapter
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