Problem 33
Question
By what factor does \(\left[\mathrm{H}^{+}\right]\) change for a pH change of (a) 3.0 units, (b) 0.3 units?
Step-by-Step Solution
Verified Answer
The concentration of hydrogen ions (\([\mathrm{H}^{+}]\)) changes by a factor of (a) \(10^{-3}\) or \(0.001\) for a pH change of 3.0 units, and (b) \(10^{-0.3}\) or approximately \(0.501\) for a pH change of 0.3 units.
1Step 1: Calculate the initial and final pH values
We are given that the pH change is 3.0 units. Let the initial pH be \(pH_{i}\) and the final pH be \(pH_{f}\). So, we can write \(pH_{f} = pH_{i} + 3\).
2Step 2: Use the pH formula to find the change in H+ concentration
We know that \(pH = -\log_{10}([\mathrm{H}^{+}])\). Thus, we have:
Initial H+ concentration: \([\mathrm{H}^{+}]_{i}=10^{-pH_{i}}\)
Final H+ concentration: \([\mathrm{H}^{+}]_{f}=10^{-pH_{f}}=10^{-(pH_{i}+3)}\)
3Step 3: Calculate the factor by which the H+ concentration changes
We have to find the factor \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}}\):
\(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = \frac{10^{-(pH_{i}+3)}}{10^{-pH_{i}}}\)
By dividing exponents:
\(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = 10^{-3}\)
So the H+ concentration changes by a factor of \(10^{-3}\) or \(0.001\).
(b) For a pH change of 0.3 units:
4Step 1: Calculate the initial and final pH values
We are given that the pH change is 0.3 units. We can write \(pH_{f} = pH_{i} + 0.3\).
5Step 2: Use the pH formula to find the change in H+ concentration
We have:
Initial H+ concentration: \([\mathrm{H}^{+}]_{i}=10^{-pH_{i}}\)
Final H+ concentration: \([\mathrm{H}^{+}]_{f}=10^{-pH_{f}}=10^{-(pH_{i}+0.3)}\)
6Step 3: Calculate the factor by which the H+ concentration changes
We have to find the factor \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}}\):
\(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = \frac{10^{-(pH_{i}+0.3)}}{10^{-pH_{i}}}\)
By dividing exponents:
\(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = 10^{-0.3}\)
So the H+ concentration changes by a factor of \(10^{-0.3}\) or approximately \(0.501\).
Key Concepts
Hydrogen Ion ConcentrationLogarithmic ScaleAcid-Base Chemistry
Hydrogen Ion Concentration
Hydrogen ion concentration, represented as \([\mathrm{H}^{+}]\), is a crucial measure in chemistry. It helps us understand the acidity or alkalinity of a solution. When we talk about the concentration of hydrogen ions, we're essentially discussing the number of hydrogen ions present in a given volume of solution.
Here's why it's important:
Here's why it's important:
- High hydrogen ion concentration indicates an acidic solution.
- Low hydrogen ion concentration suggests a basic or alkaline solution.
Logarithmic Scale
The logarithmic scale is a unique way to express quantities that vary over large ranges. In terms of pH, this scale is used to measure hydrogen ion concentrations in solutions.
\[ pH = -\log_{10}([\mathrm{H}^{+}]) \]
Therefore, small changes in pH imply substantial shifts in hydrogen ion concentrations, making the logarithmic scale effective in illustrating these differences.
An essential feature:
- Every whole number change in pH corresponds to a tenfold change in hydrogen ion concentration.
\[ pH = -\log_{10}([\mathrm{H}^{+}]) \]
Therefore, small changes in pH imply substantial shifts in hydrogen ion concentrations, making the logarithmic scale effective in illustrating these differences.
Acid-Base Chemistry
Acid-base chemistry deals with the study of acids and bases, including their behaviors and reactions in solutions. It's fundamental to understand how pH affects solutions on a molecular level.
Here are some key points:
Here are some key points:
- Acids release hydrogen ions (\([\mathrm{H}^{+}]\)) in solution, thereby increasing acidity.
- Bases remove hydrogen ions, reducing acidity and increasing pH.
- pH is a scale used to specify acidity or basicity, ranging from 0-14.
Other exercises in this chapter
Problem 31
At the boiling point of water \(\left(100^{\circ} \mathrm{C}\right), K_{w}=5.6 \times 10^{-13} .\) Calculate \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm
View solution Problem 32
Deuterium oxide \(\left(\mathrm{D}_{2} \mathrm{O},\right.\) where \(\mathrm{D}\) is deuterium, the hydrogen- 2 isotope) has an ion-product constant, \(K_{w}\),
View solution Problem 34
Consider two solutions, solution A and solution B. [H \(\left.^{+}\right]\) in solution A is 25 times greater than that in solution \(B\). What is the differenc
View solution Problem 37
The average \(\mathrm{pH}\) of normal arterial blood is 7.40 . At normal body temperature \(\left(37^{\circ} \mathrm{C}\right), K_{w}=2.4 \times 10^{-14} .\) Ca
View solution