Problem 33
Question
(a) Write the half-reaction that occurs at an oxygen electrode in acidic aqueous solution when it serves as the cathode of a voltaic cell. (b) Write the half-reaction that occurs at an oxygen electrode in acidic aqueous solution when it serves as the anode of a voltaic cell. (c) What is standard about the standard oxygen electrode?
Step-by-Step Solution
Verified Answer
(a) \(O_2 + 4H^+ + 4e^- \rightarrow 2H_2O\). (b) \(2H_2O \rightarrow O_2 + 4H^+ + 4e^-\). (c) "Standard" refers to measurement conditions: 1 atm, 25°C, 1 M concentration.
1Step 1: Understanding the cathode reaction
At the cathode of a voltaic cell, reduction occurs. For an oxygen electrode in acidic solution, the relevant half-reaction involves the reduction of \({O_2}\). Oxygen will gain electrons to form water. The balanced half-reaction in acidic solution is: \(O_2(g) + 4H^+(aq) + 4e^- \rightarrow 2H_2O(l)\).
2Step 2: Understanding the anode reaction
At the anode of a voltaic cell, oxidation occurs. For an oxygen electrode in acidic solution, the relevant half-reaction involves the oxidation of water to form oxygen gas. The balanced half-reaction in acidic solution is: \(2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^-\).
3Step 3: Understanding the standard condition
A standard electrode, such as the standard oxygen electrode, is characterized by its conditions: 25°C (298 K), 1 atm pressure for gases, and 1 M concentration for solutions. These conditions ensure reproducibility of measurements. The standard hydrogen electrode (SHE) is also used as a reference point to measure standard electrode potentials.
Key Concepts
Understanding Half-ReactionsThe Significance of Standard ElectrodesExploring Redox Reactions in Voltaic Cells
Understanding Half-Reactions
In a voltaic cell, chemical reactions are divided into two parts known as half-reactions. Each half-reaction takes place at different electrodes: cathode and anode. This helps in understanding the specific processes of oxidation and reduction.
For instance, during a reaction at the cathode, reduction of a substance occurs. In the context of an oxygen electrode in an acidic aqueous solution, the oxygen molecule undergoes reduction by gaining electrons and protons to form water. This specific half-reaction can be represented as follows:
For instance, during a reaction at the cathode, reduction of a substance occurs. In the context of an oxygen electrode in an acidic aqueous solution, the oxygen molecule undergoes reduction by gaining electrons and protons to form water. This specific half-reaction can be represented as follows:
- Oxygen gas, \(O_2(g)\), combines with hydrogen ions, \(4H^+(aq)\), and electrons, \(4e^-\), to produce water, \(2H_2O(l)\).
- Water, \(2H_2O(l)\), is oxidized to form oxygen gas, \(O_2(g)\), hydrogen ions, \(4H^+(aq)\), and electrons, \(4e^-\).
The Significance of Standard Electrodes
A standard electrode provides a baseline to measure and compare the electrical potential of half-reactions under consistent conditions. These conditions usually include:
- Temperature of 25°C (or 298 K).
- Pressure of 1 atmosphere for any gases involved.
- Concentration of 1 Molarity for aqueous solutions.
Exploring Redox Reactions in Voltaic Cells
Redox reactions are fundamental to the operation of voltaic cells. These included reactions are characterized by the transfer of electrons. The term 'redox' is a shorthand for reduction-oxidation reactions. Here’s what that means:
- Reduction refers to the gain of electrons by a chemical species.
- Oxidation refers to the loss of electrons by a chemical species.
- The oxygen at the cathode receives electrons—it's reduced, forming water.
- Water at the anode loses electrons—it’s oxidized to form oxygen gas.
Other exercises in this chapter
Problem 31
(a) What is the definition of the volt? (b) Do all voltaic cells produce a positive cell potential?
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