Problem 33
Question
A Function with Specified Limits Sketch the graph of an example of a function \(f\) that satisfies all of the following conditions. $$\begin{aligned} &\lim _{x \rightarrow 0^{-}} f(x)=2 \quad \lim _{x \rightarrow 0^{+}} f(x)=0\\\ &\lim _{x \rightarrow 2} f(x)=1 \quad f(0)=2 \quad f(2)=3 \end{aligned}$$ How many such functions are there?
Step-by-Step Solution
Verified Answer
There are infinitely many functions that satisfy these conditions.
1Step 1: Understanding the Problem
We need to create a function that satisfies certain limit conditions and specific function values. The limits will dictate the behavior of the graph as it approaches specific points.
2Step 2: Interpreting Limit at x=0
The limit \( \lim_{{x \rightarrow 0^{-}}} f(x)=2 \) means as \( x \) approaches 0 from the left, \( f(x) \) needs to approach 2. Meanwhile, \( \lim_{{x \rightarrow 0^{+}}} f(x)=0 \) indicates that as \( x \) approaches 0 from the right, \( f(x) \) needs to approach 0. This implies a jump discontinuity or a sharp turn at \( x=0 \).
3Step 3: Interpreting Function Value at x=0
Since \( f(0) = 2 \), at exactly \( x=0 \), the function value is 2. This confirms the jump discontinuity hinted by the previous step.
4Step 4: Interpreting Limit at x=2
The limit \( \lim_{{x \rightarrow 2}} f(x)=1 \) implies that as \( x \) approaches 2 from either direction, \( f(x) \) must approach 1. However, this does not mean the function necessarily equals 1 at \( x=2 \).
5Step 5: Interpreting Function Value at x=2
We know that \( f(2)=3 \). This means that at \( x=2 \), the function differs from its approaching value, indicating a removable or point discontinuity at \( x=2 \).
6Step 6: Sketching a Possible Function
Considering all the above conditions, sketch a function that has a sharp edge at \( x=0 \), with values approaching 2 from the left and 0 from the right, and facing a different value at \( x=2 \) than approaching but with the point value of 3.
7Step 7: Assessing the Number of Possible Functions
There are infinitely many functions that can satisfy these conditions, as long as they meet the specified limits and function values exactly at \( x=0 \) and \( x=2 \).
Key Concepts
Jump DiscontinuityRemovable DiscontinuitySketching Graphs
Jump Discontinuity
When discussing limits and graphing functions, one might encounter a jump discontinuity. This term describes a scenario where the graph of a function experiences an abrupt leap from one value to another as the input approaches a certain point from different directions. In simpler terms, imagine the graph 'jumping' to a different height without any gradual change.
Consider our example in this exercise:
This discontinuity is visually represented on a graph by a sharp change or a sudden 'jump' and is quite common when encountering limits.
Consider our example in this exercise:
- As \( x \) approaches 0 from the left, \( f(x) \) approaches 2 (\( \lim_{{x \rightarrow 0^{-}}} f(x)=2 \)).
- However, approaching from the right, \( f(x) \) approaches 0 (\( \lim_{{x \rightarrow 0^{+}}} f(x)=0 \)).
This discontinuity is visually represented on a graph by a sharp change or a sudden 'jump' and is quite common when encountering limits.
Removable Discontinuity
A removable discontinuity is another type of imperfection that can occur on a graph. It resembles a 'hole' where the graph could have been seamlessly connected, yet isn't, due to a specific function value different from the approaching limits.
In the exercise:
In the exercise:
- We see that as \( x \) approaches 2, \( f(x) \) closes in on 1, indicated by \( \lim_{{x \rightarrow 2}} f(x)=1 \).
- However, the function value at \( x=2 \) is defined as 3 (\( f(2) = 3 \)).
Sketching Graphs
Creating a visual representation of function behaviors through sketching graphs is a vital part of understanding limits and discontinuities. It allows you to see where discontinuities occur and how the function behaves around those points.
In this exercise, we have:
In this exercise, we have:
- A sharp change at \( x=0 \), where the function jumps from one side to another, typical of a jump discontinuity.
- A different value where the function meets at \( x=2 \) despite its limits, indicating a removable discontinuity.
Other exercises in this chapter
Problem 32
Finding Limits Evaluate the limit if it exists. $$\lim _{t \rightarrow 4} \frac{\frac{1}{\sqrt{t}}-\frac{1}{2}}{t-4}$$
View solution Problem 32
Limits of Sequences If the sequence with the given \(n\) th term is convergent, find its limit. If it is divergent, explain why. $$a_{n}=\frac{5}{n}\left(n+\fra
View solution Problem 33
The given limit represents the derivative of a function \(f\) at a number \(a\). Find \(f\) and \(a\) $$\lim _{h \rightarrow 0} \frac{(1+h)^{10}-1}{h}$$
View solution Problem 33
Find the limit, and use a graphing device to confirm your result graphically. $$\lim _{x \rightarrow 1} \frac{x^{2}-1}{\sqrt{x}-1}$$
View solution