Problem 33
Question
\(6(3 u)=(6 \cdot 3) u\)
Step-by-Step Solution
Verified Answer
Yes, \( 6(3u) = (6 \cdot 3)u \) simplifies to \(18u = 18u\).
1Step 1: Identify the Expression
Notice the given expression: \[ 6(3u) = (6 \cdot 3)u \]We need to verify whether both sides of the equation are equal.
2Step 2: Simplify Inside the Parentheses
Simplify the term inside the parentheses on the left-hand side: \[ 6(3u) = 6 \cdot 3 \cdot u \]
3Step 3: Perform the Multiplication
Multiply the constants on the left-hand side: \[ 6 \cdot 3 \cdot u = 18u \]
4Step 4: Compare Both Sides
Now, compare the simplified left-hand side to the right-hand side: \[ 18u = 18u \]Both sides are equal, confirming that the original equation is true.
Key Concepts
Algebraic ExpressionsSimplificationMultiplication
Algebraic Expressions
Algebraic expressions are mathematical phrases that include numbers, variables, and operation symbols. In our exercise, we have the expression \(6(3u) = (6 \cdot 3)u\). Here, \(3u\) is the algebraic part, with \(3\) being the coefficient and \(u\) the variable. Algebraic expressions can be manipulated in various ways using algebraic properties like the Distributive Property. The Distributive Property helps in breaking down expressions to make simplification easier. Learning to work with these expressions is a crucial skill in algebra and mathematics overall. Understanding how to recognize and manipulate algebraic components will greatly assist in solving more complex problems as you progress.
Simplification
Simplification is the process of reducing an algebraic expression to its simplest form. In the exercise, we start with simplifying \(6(3u)\). To do this, we look inside the parentheses and see that \(3u\) can be separated. Applying the Distributive Property, \(6(3u)\) becomes \(6 \cdot 3 \cdot u\). This step is critical because it sets up the expression for easier multiplication and further simplification. Simplification usually involves:
- Combining like terms
- Using distributive property
- Reducing fractions, if any
Multiplication
Multiplication in algebra follows the same basic principles as arithmetic multiplication but often involves variables. In our exercise, once we have broken down \(6(3u)\) to \(6 \cdot 3 \cdot u\), we perform the multiplication of the constants first. So, \(6 \cdot 3 = 18\), and then we multiply by the variable \(u\), which gives us \(18u\). This ability to distribute and multiply is essential for simplifying and solving algebraic expressions and equations. It's important to follow the order of operations (sometimes remembered as PEMDAS) to ensure calculations are done correctly. By practicing these steps, you can solve similar problems with ease.
Other exercises in this chapter
Problem 33
Evaluate \(8 \mathrm{~km}+4 \mathrm{~m}\). Write the answer in kilometers.
View solution Problem 33
Find the percent of vehicles belonging to residents that can be parked in legal curb spaces. Round to the nearest percent. The need for extra parking is clear:
View solution Problem 33
\(2^{3}\)
View solution Problem 34
Evaluate \(12 \mathrm{~kg}+54 \mathrm{~g}\). Write the answer in kilograms.
View solution