Problem 33
Question
\(29-34\) Simplify the expression by using a Double-Angle Formula or a Half- Angle Formula. $$ \begin{array}{ll}{\text { (a) } \frac{\sin 8^{\circ}}{1+\cos 8^{\circ}}} & {\text { (b) } \frac{1-\cos 4 \theta}{\sin 4 \theta}}\end{array} $$
Step-by-Step Solution
Verified Answer
(a) \( \tan 4^{\circ} \) and (b) \( \tan 2\theta \)
1Step 1: Identify Applicable Formula for Part (a)
For part (a), let's first focus on the expression \( \frac{\sin 8^{\circ}}{1+\cos 8^{\circ}} \). We'll use the identity: \( \sin \theta = 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} \) and \( 1+\cos \theta = 2 \cos^2 \frac{\theta}{2} \). These are derived from the double-angle formulas.
2Step 2: Simplify Part (a) Using Double Angle Identities
Applying the identities from Step 1, we get:\[ \sin 8^{\circ} = 2 \sin 4^{\circ} \cos 4^{\circ} \] and\[ 1 + \cos 8^{\circ} = 2 \cos^2 4^{\circ} \]Substitute these into the expression: \[ \frac{2 \sin 4^{\circ} \cos 4^{\circ}}{2 \cos^2 4^{\circ}} = \frac{\sin 4^{\circ}}{\cos 4^{\circ}} = \tan 4^{\circ} \]
3Step 3: Identify Applicable Formula for Part (b)
For part (b), the expression is \( \frac{1-\cos 4 \theta}{\sin 4 \theta} \). We can use the identity \( 1 - \cos \theta = 2 \sin^2 \frac{\theta}{2} \).
4Step 4: Simplify Part (b) Using Half-Angle Identity
Applying the identity from Step 3, we have:\[ 1 - \cos 4\theta = 2 \sin^2 2\theta \] Substituting in the original expression, we get:\[ \frac{2 \sin^2 2\theta}{\sin 4\theta} = \frac{2 \sin^2 2\theta}{2 \sin 2\theta \cos 2\theta} = \frac{\sin 2\theta}{\cos 2\theta} = \tan 2\theta \]
Key Concepts
Trigonometric IdentitiesSimplifying Trigonometric ExpressionsTan Function
Trigonometric Identities
Trigonometric identities are equations that relate the trigonometric functions to each other. These identities are crucial in simplifying complex trigonometric expressions by providing standard formulas that can be applied.
Some of the most commonly used identities include:
Some of the most commonly used identities include:
- Pythagorean Identities, like \( \sin^2\theta + \cos^2\theta = 1 \)
- Reciprocal Identities, such as \( \sin\theta = \frac{1}{\csc\theta} \)
- Double-Angle and Half-Angle Formulas, like \( \sin 2\theta = 2 \sin\theta \cos\theta \)
Simplifying Trigonometric Expressions
Simplifying trigonometric expressions often involves using identities to rewrite expressions in a more manageable form. The goal is to convert complex fractions or products into more straightforward expressions.
By using known identities, you can break down a problem into smaller, more easily solvable parts. For part (a) of the original problem, the expression \[ \frac{\sin 8^{\circ}}{1+\cos 8^{\circ}} \] is simplified using the double-angle formulas.
Initially, these identities transform the expression into \[ \frac{2 \sin 4^{\circ} \cos 4^{\circ}}{2 \cos^2 4^{\circ}} \. \]This expression simplifies further to yield \( \tan 4^{\circ} \). A similar process happens in part (b), where the expression \[ \frac{1-\cos 4\theta}{\sin 4\theta} \] is tackled using half-angle identities to eventually simplify to \( \tan 2\theta \). Understanding how to rearrange and substitute using these identities is the core of simplifying any trigonometric problem.
By using known identities, you can break down a problem into smaller, more easily solvable parts. For part (a) of the original problem, the expression \[ \frac{\sin 8^{\circ}}{1+\cos 8^{\circ}} \] is simplified using the double-angle formulas.
Initially, these identities transform the expression into \[ \frac{2 \sin 4^{\circ} \cos 4^{\circ}}{2 \cos^2 4^{\circ}} \. \]This expression simplifies further to yield \( \tan 4^{\circ} \). A similar process happens in part (b), where the expression \[ \frac{1-\cos 4\theta}{\sin 4\theta} \] is tackled using half-angle identities to eventually simplify to \( \tan 2\theta \). Understanding how to rearrange and substitute using these identities is the core of simplifying any trigonometric problem.
Tan Function
The tangent function, denoted as tan, is one of the primary trigonometric functions. It is defined as the ratio of the sine and cosine of an angle: \( \tan\theta = \frac{\sin\theta}{\cos\theta} \). This function exhibits periodic behavior and has a period of \( \pi \) radians (or 180 degrees).
In the context of this problem, both parts (a) and (b) are simplified to involve the tangent function through their respective processes.
By recognizing when expressions can be reduced to a simple tangent function, complex problems are made significantly easier, making it a powerful tool in your trigonometry toolkit.
In the context of this problem, both parts (a) and (b) are simplified to involve the tangent function through their respective processes.
- Part (a) uses the identity relations to arrive at \( \tan 4^{\circ} \).
- Part (b) simplifies down to \( \tan 2\theta \).
By recognizing when expressions can be reduced to a simple tangent function, complex problems are made significantly easier, making it a powerful tool in your trigonometry toolkit.
Other exercises in this chapter
Problem 33
\(17-34\) . An equation is given. (a) Find all solutions of the equation. (b) Find the solutions in the interval \([0,2 \pi) .\) $$ 2 \sin \theta \tan \theta-\t
View solution Problem 33
Prove the identity. $$ \sin (x+y)-\sin (x-y)=2 \cos x \sin y $$
View solution Problem 33
\(25-38\) . Find all solutions of the given equation. $$ 2 \cos ^{2} \theta-1=0 $$
View solution Problem 33
Verify the identity. $$ \sin B+\cos B \cot B=\csc B $$
View solution