Problem 33
Question
\({ }^{227}\) Ac has a half-life of \(21.8\) years with respect to radioactive decay. The decay follows two parallel paths, one leading to \({ }^{27} \mathrm{Th}\) and the other to \({ }^{223} \mathrm{Fr}\). The percentage yields of these two daughter nuclides are \(1.2\) and \(98.8\) respectively. What are the decay constants \((\lambda)\) for each of the separate paths?
Step-by-Step Solution
Verified Answer
The decay constants are 0.00038 per year for \(^{223}\text{Th}\) and 0.03143 per year for \(^{223}\text{Fr}\).
1Step 1: Calculate the Total Decay Constant
The formula for the decay constant (\( \lambda \)) in terms of half-life (\( t_{1/2} \)) is \( \lambda = \frac{\ln(2)}{t_{1/2}} \). For \( ^{227}\text{Ac} \), the half-life \( t_{1/2} \) is 21.8 years. \( \lambda = \frac{\ln(2)}{21.8} \approx 0.03181 \text{ per year}\). This is the total decay constant for \( ^{227}\text{Ac} \).
2Step 2: Understanding Parallel Pathway Decay
Since \( ^{227}\text{Ac} \) decays via two parallel pathways, each path shares the total decay constant based on its percentage yield. We need to distribute the total decay constant by these percentage yields into two separate decay constants for \( ^{223}\text{Th} \) and \( ^{223}\text{Fr} \).
3Step 3: Calculate the Decay Constant for \( ^{223}\text{Th} \)
The percentage yield to \( ^{223}\text{Th} \) is 1.2%. To find its decay constant:\[ \lambda_{\text{Th}} = \frac{1.2}{100} \times \lambda = \frac{1.2}{100} \times 0.03181 \approx 0.00038172 \text{ per year} \]
4Step 4: Calculate the Decay Constant for \( ^{223}\text{Fr} \)
The percentage yield to \( ^{223}\text{Fr} \) is 98.8%. Hence, its decay constant is:\[ \lambda_{\text{Fr}} = \frac{98.8}{100} \times \lambda = \frac{98.8}{100} \times 0.03181 \approx 0.03142828 \text{ per year} \]
Key Concepts
Understanding Half-Life CalculationsDecay Constant DemystifiedExploring Parallel Decay Pathways
Understanding Half-Life Calculations
Half-life is an essential concept when studying radioactive decay. It is defined as the time required for half of a radioactive substance to undergo decay. This is a constant property of each radioactive isotope and provides insights into its stability. To find the half-life of a radioactive substance, you use the formula: \[ t_{1/2} = \frac{\ln(2)}{\lambda} \]where:
- \( t_{1/2} \) is the half-life.
- \( \lambda \) is the decay constant.
- \( \ln(2) \approx 0.693 \), which is the natural logarithm of 2.
Decay Constant Demystified
The decay constant \( \lambda \) is a key factor in understanding the rate of radioactive decay. It represents the probability per unit time that a nucleus will decay. The relationship between half-life and decay constant is straightforward using the formula:\[ \lambda = \frac{\ln(2)}{t_{1/2}} \]where:
- \( \lambda \) is the decay constant.
- \( t_{1/2} \) is the half-life.
Exploring Parallel Decay Pathways
In certain radioactive decays, a parent isotope can decay into more than one type of daughter isotope through different paths. These are known as parallel decay pathways. For example, \( ^{227}\text{Ac} \) has two parallel decay paths:
- To \( ^{223}\text{Th} \) with a 1.2% yield.
- To \( ^{223}\text{Fr} \) with a 98.8% yield.
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