Problem 32
Question
Write the quotient in simplest form. $$\frac{16 x^{2}}{8 x} \div \frac{4 x^{2}}{16 x}$$
Step-by-Step Solution
Verified Answer
The simplest form of the given expression is \(8x\).
1Step 1: Apply the concept of Keep-Change-Flip
Transform the division of fractions to multiplication by applying the Keep-Change-Flip rule. Therefore, the expression becomes \(\frac{16 x^{2}}{8 x} * \frac{16 x}{4 x^{2}}\).
2Step 2: Simplify the Numerators and Denominators
Simplify the fractions before multiplying: \(2x * 4 = 8x\)
3Step 3: Apply laws of exponents
When dividing terms with the same base (in this case 'x'), subtract the exponents. \(8x^{1} = 8x\)
Key Concepts
Keep-Change-FlipLaws of ExponentsFraction Division
Keep-Change-Flip
When it comes to dividing fractions, the "Keep-Change-Flip" method is your best friend. It transforms division into a more straightforward multiplication problem.
- **Keep** the first fraction as it is.
- **Change** the division sign to a multiplication sign.
- **Flip** the second fraction to its reciprocal.
Laws of Exponents
The laws of exponents play a vital role in simplifying expressions that involve powers of a variable. When you're dealing with exponents, it's important to remember the subtraction rule for division.
For any base \( a \), the rule is: \( a^{m} \div a^{n} = a^{m-n} \). This means when you divide like bases, you subtract the exponents.
For any base \( a \), the rule is: \( a^{m} \div a^{n} = a^{m-n} \). This means when you divide like bases, you subtract the exponents.
- In the given solution, when multiplying \( 16x^2 \cdot \frac{16x}{4x^2} \), you're simplifying by subtracting the exponents of \( x \).
- So, \( x^{2} \div x^{1} = x^{2-1} = x \), which simplifies part of the expression.
Fraction Division
Dividing fractions in algebra involves understanding the basic principles of fraction arithmetic combined with algebraic manipulation. The process of dividing one fraction by another can be simplified considerably by following systematic steps.
First, using Keep-Change-Flip, convert the division into multiplication. This makes the problem much easier to handle.
Next, simplify the fractions individually. In our case, \( \frac{16 x^{2}}{8 x} \) simplifies to \( 2x \), and \( \frac{16 x}{4 x^{2}} \) simplifies to \( \frac{4}{x} \).
Finally, multiply these simplified fractions. The product \( 2x \times \frac{4}{x} \) is \( 8 \), after canceling \( x \) from the numerator and the denominator.
Hence, understanding each part of fraction division helps streamline solving algebraic fractions and reduces errors.
First, using Keep-Change-Flip, convert the division into multiplication. This makes the problem much easier to handle.
Next, simplify the fractions individually. In our case, \( \frac{16 x^{2}}{8 x} \) simplifies to \( 2x \), and \( \frac{16 x}{4 x^{2}} \) simplifies to \( \frac{4}{x} \).
Finally, multiply these simplified fractions. The product \( 2x \times \frac{4}{x} \) is \( 8 \), after canceling \( x \) from the numerator and the denominator.
Hence, understanding each part of fraction division helps streamline solving algebraic fractions and reduces errors.
Other exercises in this chapter
Problem 32
Write the difference in simplest form. $$ \frac{5 c}{15}-\frac{2+c}{25 c} $$
View solution Problem 32
Solve the equation. Check your solutions. $$ \frac{x-3}{18}=\frac{3}{x} $$
View solution Problem 32
Simplify the expression. If not possible, write already in simplest form. $$\frac{x^{3}+9 x^{2}+14 x}{x^{2}-4}$$
View solution Problem 33
Find and correct the error. $$ \begin{aligned} &\frac{x+2}{y+3}+\frac{y-4}{y+3}=\frac{(y+2)(y-4)}{(y+3)^{2}}\\\ &=\frac{y^{2}-2 y-8}{y^{2}+6 y+9} \end{aligned}
View solution