Problem 32
Question
Write each linear system as a matrix equation in the form \(A X=B\), where \(A\) is the coefficient matrix and \(B\) is the constant matrix. $$ \text { 32. }\left\\{\begin{aligned} x+4 y-z &=3 \\ x+3 y-2 z &=5 \\ 2 x+7 y-5 z &=12 \end{aligned}\right. $$
Step-by-Step Solution
Verified Answer
The matrix form of the given system of equations is given by \(A X = B\), where \(A = \[[1, 4, -1], [1, 3, -2], [2, 7, -5]\]\), \(X = \[[x], [y], [z]\]\), and \(B = \[[3], [5], [12]\]\).
1Step 1: Identify matrix A
The coefficient matrix \(A\) is consisting of the coefficients of the variables \(x\), \(y\), and \(z\). In our given system, we can read off these coefficients to create the matrix A, which becomes \(A = \[[1, 4, -1], [1, 3, -2], [2, 7, -5]\]\).
2Step 2: Identify matrix X
The solution matrix \(X\) consists of the variables of the system. In this case, the variables are \(x\), \(y\), and \(z\), so our matrix \(X\) becomes \(X = \[[x], [y], [z]\]\).
3Step 3: Identify matrix B
The constant matrix \(B\) consists of the constants on the right side of the system equations. These can be read off from the system to form the matrix \(B\), which becomes \(B = \[[3], [5], [12]\]\).
Key Concepts
Linear SystemsCoefficient MatrixConstant Matrix
Linear Systems
Linear systems are sets of equations where each equation is linear. Linear means that the variables are only to the first power and combined using operators like addition and subtraction. For example, in the equations provided in the problem, we see each equation fits these criteria. Linear systems can have infinite solutions, one solution, or no solution. To solve them, we often use methods like substitution, elimination, or matrix equations.
- They typically appear in the form of several equations together.
- They involve relationships represented by straight lines when graphed.
Coefficient Matrix
A coefficient matrix is a matrix consisting solely of the coefficients of the variables from each equation in a linear system. In the context of matrices, coefficients are the numbers that multiply the variables.
In our example, the coefficient matrix, denoted as \( A \), is comprised of the numerical coefficients for \( x \), \( y \), and \( z \) from each equation of the linear system.
This matrix is vital when converting a system of equations into matrix form, simplifying the process of using matrix operations to find solutions.
In our example, the coefficient matrix, denoted as \( A \), is comprised of the numerical coefficients for \( x \), \( y \), and \( z \) from each equation of the linear system.
- It describes how each variable contributes to each equation.
- It's a neat way to organize information, making it easier for calculations with computers or by hand.
This matrix is vital when converting a system of equations into matrix form, simplifying the process of using matrix operations to find solutions.
Constant Matrix
The constant matrix, denoted here as \( B \), consists of the constants from the equations in the linear system. These constants are the numbers without variables on the right side of each equation. Simply put, they are what you get when substituting all variables on one side of the equation.
In our given system:
In our given system:
- The constants are 3, 5, and 12.
- These form a single column matrix, aligning with each equation.
Other exercises in this chapter
Problem 32
Find (if possible) the following matrices: a. \(A B\) b. \(B A\) $$ A=\left[\begin{array}{rrr} {1} & {-1} & {1} \\ {5} & {0} & {-2} \\ {3} & {-2} & {2} \end{arr
View solution Problem 32
Solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{aligned} 3 a+b-c &
View solution Problem 32
Use Cramer's Rule to solve each system. $$\left\\{\begin{aligned}x-3 y+z &=-2 \\\x+2 y &=8 \\\2 x-y &=1\end{aligned}\right.$$
View solution Problem 33
Find (if possible) the following matrices: a. \(A B\) b. \(B A\) $$ A=\left[\begin{array}{ll} {4} & {2} \\ {6} & {1} \\ {3} & {5} \end{array}\right], \quad B=\l
View solution