Problem 32
Question
Write an equation that describes the equilibrium that exists when the weak acid benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}\right)\) dissolves in water. Identify each of the four species in solution as either Bronsted acids or Bronsted bases. Does the equilibrium favor the products or the reactants? (In acting as an acid, the \(-\mathrm{CO}_{2} \mathrm{H}\) group supplies \(\left.\mathrm{H}^{+} \text {to } \mathrm{form} \mathrm{H}_{3} \mathrm{O}^{+} .\right)\)
Step-by-Step Solution
Verified Answer
Reactants are favored; benzoic acid is the Bronsted acid, and water is the Bronsted base.
1Step 1: Writing the Dissolution Equation
Start by writing the chemical equation for the dissolution of benzoic acid in water. Benzoic acid \((\mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2\mathrm{H})\) donates a proton \((\mathrm{H}^+)\) to water, which acts as a Bronsted base, forming hydronium \(\mathrm{H}_3\mathrm{O}^+\) and benzoate ion \(\mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2^-\). The equation is: \[ \mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2\mathrm{H}(aq) + \mathrm{H}_2\mathrm{O}(l) \rightleftharpoons \mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2^-(aq) + \mathrm{H}_3\mathrm{O}^+(aq) \]
2Step 2: Identify Bronsted Acids and Bases
In the equation, identify each species as a Bronsted acid or base. - Benzoic acid \(\mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2\mathrm{H} \) acts as a Bronsted acid because it donates a proton. - Water \(\mathrm{H}_2\mathrm{O}\) acts as a Bronsted base because it accepts a proton to form \(\mathrm{H}_3\mathrm{O}^+\). - Benzoate ion \(\mathrm{C}_6\mathrm{H}_5\mathrm{CO}_2^-\) is a Bronsted base because it results from the acid donating a proton. - Hydronium ion \(\mathrm{H}_3\mathrm{O}^+\) acts as a Bronsted acid in the reverse reaction because it can donate a proton.
3Step 3: Determining Equilibrium Favor
To determine which side the equilibrium favors, consider the strength of the acids and bases.
- Benzoic acid is a weak acid, so it does not dissociate completely in solution, indicating the reactants are favored.
- The equilibrium, therefore, largely remains towards the left side (reactants).
Key Concepts
Bronsted acidsWeak acidsChemical equilibriumWeak bases
Bronsted acids
In the world of chemistry, understanding the nature of acids and bases is crucial. Bronsted acids, named after the scientist Johannes Bronsted, are substances that can donate a proton (
H^+
) to another substance. This concept is fundamental when discussing equilibrium reactions.
When benzoic acid (
C_6H_5CO_2H
) dissolves in water, it acts as a Bronsted acid by donating a proton to a water molecule. This ability to donate a proton is what characterizes a Bronsted acid.
- In the reaction, benzoic acid is the proton donor.
- Water, which accepts the proton, plays the role of a Bronsted base in this context.
Weak acids
Weak acids, like benzoic acid, do not fully dissociate in water. This incomplete dissociation is a key feature that differentiates them from strong acids.
- Weak acids establish an equilibrium in solution, meaning they partially ionize.
- This results in a mixture of ions and un-ionized acid molecules in the solution.
Chemical equilibrium
Chemical equilibrium occurs when the rates of the forward and reverse reactions are equal, leading to continuous dynamic balance.
In the equilibrium reaction involving benzoic acid, both the forward reaction (formation of benzoate and hydronium ions) and the reverse reaction (recombination to form benzoic acid and water) occur simultaneously.
- The equilibrium is said to favor the reactants because benzoic acid is a weak acid.
- As a result, there is more undissociated benzoic acid compared to the ions produced.
Weak bases
In an equilibrium involving a weak acid like benzoic acid, the concept of weak bases also plays a crucial role.
A weak base is a species that does not completely accept a proton in a solution. This is observed in benzoate ion (
C_6H_5CO_2^-
), which is formed as a conjugate base during the dissociation of benzoic acid in water.
- Benzoate ion acts as a weak base because it can accept a proton from hydronium ions to reform benzoic acid.
- In such reactions, both weak acids and weak bases exist in equilibrium with their conjugates.
Other exercises in this chapter
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