Problem 32
Question
Which of the following is not an example of tautomeric equilibrium? (a) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{C}=\mathrm{O} \rightleftharpoons \mathrm{CH}_{2}-\mathrm{CH}=\mathrm{C}-\mathrm{O}\) (b) \(-\mathrm{N}=\mathrm{N}-\mathrm{NH} \rightleftharpoons \mathrm{NH}-\mathrm{N}=\mathrm{N}\) (c) \(>\mathrm{CH}-\mathrm{N}=\mathrm{O} \rightleftharpoons>\mathrm{C}=\mathrm{N}-\mathrm{OH}\) (d) \(-\mathrm{NH}-\mathrm{C}=\mathrm{O} \rightleftharpoons-\mathrm{N}=\mathrm{C}-\mathrm{OH}\)
Step-by-Step Solution
Verified Answer
Option (b) is not a typical example of tautomeric equilibrium.
1Step 1: Understanding Tautomeric Equilibrium
Tautomeric equilibrium involves the shifting of a hydrogen atom and a double bond within a molecule resulting in isomeric structures called tautomers. This process typically involves keto-enol or amine-iminol transformations.
2Step 2: Analyzing Option (a)
In option (a), we have \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{C}=\mathrm{O}\rightleftharpoons \mathrm{CH}_{2}-\mathrm{CH}=\mathrm{C}-\mathrm{O}\). This represents a keto-enol tautomerism due to the movement of a hydrogen and a double bond. Thus, it is a valid tautomeric equilibrium.
3Step 3: Analyzing Option (b)
In option (b), the structure \(-\mathrm{N}=\mathrm{N}-\mathrm{NH} \rightleftharpoons \mathrm{NH}-\mathrm{N}=\mathrm{N}\) is a rearrangement involving nitrogen. However, it does not involve the transfer of a hydrogen and a double bond characteristic of typical tautomeric equilibrium. This is not a common tautomeric shift.
4Step 4: Analyzing Option (c)
For option (c), \(>\mathrm{CH}-\mathrm{N}=\mathrm{O}\rightleftharpoons>\mathrm{C}=\mathrm{N}-\mathrm{OH}\) indicates a tautomeric shift with a change from a carbonyl group to an iminol form, a known type of tautomerism. Thus, it represents a tautomeric equilibrium.
5Step 5: Analyzing Option (d)
In option (d), \( -\mathrm{NH}-\mathrm{C}=\mathrm{O} \rightleftharpoons-\mathrm{N}=\mathrm{C}-\mathrm{OH} \) involves the movement of a hydrogen and formation of an iminol tautomer, which is characteristic of tautomeric equilibrium.
6Step 6: Conclusion
From the analysis, option (b) does not represent a typical tautomeric equilibrium as it does not conform to the common hydrogen transfer and double bond shifting convention seen in tautomerism.
Key Concepts
Keto-Enol TautomerismAmine-Iminol TransformationsHydrogen Atom Shifting
Keto-Enol Tautomerism
Keto-enol tautomerism is a fascinating molecular phenomenon often encountered in organic chemistry. It involves the shifting of a hydrogen atom and the adjustment of a double bond within a molecule. This process results in the interconversion between two isomers: the keto form and the enol form. In the keto form, the hydrogen is bonded to a carbon, which is also double-bonded to an oxygen (carbonyl group), while in the enol form, the hydrogen shifts to the oxygen, creating an alcohol group (hydroxyl group) with an adjacent carbon-carbon double bond.
Keto-enol tautomerism is significant because it often affects the chemical behavior and stability of compounds. The two forms can interconvert, yet they may not be present in equal amounts. Factors such as solvent, temperature, and the presence of a catalyst can influence which form is more dominant.
This transformation plays a crucial role in many biochemical processes and reactions, like the isomerization of pyruvate in metabolism. Understanding keto-enol tautomerism helps in grasping reaction mechanisms and predicting the properties of organic compounds.
Amine-Iminol Transformations
The amine-iminol transformation is another type of tautomerism involving nitrogen-containing compounds. In this process, a hydrogen atom shifts from nitrogen to an oxygen atom or vice versa, and an adjacent double bond rearranges accordingly. This kind of transformation is typically present in molecules containing a carbon-nitrogen double bond, which can tautomerize to form an iminol with a carbon-oxygen double bond.
Amine-iminol tautomerism plays a role in the stability and reactivity of compounds such as amino acids, and it can significantly influence the behavior of these compounds in biological systems. This equilibrium can affect how a molecule interacts with enzymes, substrates, or other biological molecules, impacting functions like protein folding or enzyme catalysis.
Factors such as pH, solvent environment, and temperature can impact the ratio of amine to iminol forms, thereby influencing the behavior of the molecule in various chemical contexts.
Hydrogen Atom Shifting
Hydrogen atom shifting is a fundamental part of tautomeric equilibria, essential to understanding both keto-enol and amine-iminol transformations. In tautomerism, a hydrogen atom moves from one atom to another within the molecule, often involving a change between single and double bonds. This simple movement can have profound effects on structural configurations and the properties of the molecules.
This shifting of hydrogen atoms is driven by the molecule seeking a more stable configuration, with energy considerations often dictating the most favored tautomeric form. In many cases, the shift can be reversible, allowing the molecule to exist in a dynamic equilibrium between different forms.
Hydrogen shifting is not only crucial for understanding tautomerism but also for broader organic processes. It is essential for various reactions and mechanisms, including acid-base chemistry, the behavior of enzymes in biochemistry, and the synthesis of complex organic molecules.
Other exercises in this chapter
Problem 30
In which structure Gauche form has less potential energy than antiform (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}+\mathrm{CH}_{2}-\mathrm{Cl}\) (b) \(\mathrm{HO}-\ma
View solution Problem 31
Tautomerism will be exhibited by (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CNO}\) (c) \(\mathrm{R}_{3}
View solution Problem 37
Geometrical isomers differ in (a) position of functional group (b) spatial arrangement of atoms (c) position of atoms (d) length of carbon chain
View solution Problem 38
Stereoisomers have different (a) Molecular formula (b) Structural formula (c) Configuration (d) Molecular mass
View solution