Problem 32
Question
What is the age of a piece of volcanic rock that has a mass ratio of argon- 40 to potassium- 40 of \(2.9 ?\) The half-life of potassium-40 by \(\beta\) decay is \(1.248 \times 10^{9} \mathrm{y}\) and by electron capture \(t_{1 / 2}=1.4 \times 10^{9} \mathrm{y}\).
Step-by-Step Solution
Verified Answer
Plug the calculated decay constant and the provided mass ratio into the elapsed time equation to find the age of the volcanic rock. Please execute the calculations to get the final result.
1Step 1: Understand the Problem
This is a problem concerning radiometric age dating. We are given a mass ratio of argon-40 to potassium-40 in a piece of volcanic rock λ=2.9. We are also given two possible half-lives of potassium-40.
2Step 2: Formulate the Decay Rate Equation
Let's utilize the radioactive decay rate equation: \( t = \frac{1}{λ} \cdot \ln(1 + \frac{N}{N_{0}}) \), where t is the elapsed time, N is the number of atoms currently present, N_{0} is the number of atoms initially present, and \(λ\) is the decay constant calculated from the half-life.
3Step 3: Calculate Decay Constant
Using the given half-life value, the decay constant \(\( λ \) can be calculated using the formula: \( λ = \frac{0.693}{t_{\frac{1}{2}}} \). Since the half-life estimation is uncertain, let's take an average of the two given values, Hence, \( λ = \frac{0.693}{((1.248 + 1.4) / 2) * 10^{9} } \). Calculating this will give us the decay constant.
4Step 4: Substitute Values to Find Elapsed Time
Substitute the given mass ratio 2.9 (= N / N_{0}) and calculated decay constant into the decay rate equation to find the elapsed time. This will give us the age of the volcanic rock.
Key Concepts
Radioactive Decay Rate EquationPotassium-40 Half-LifeArgon-40 to Potassium-40 Mass Ratio
Radioactive Decay Rate Equation
Understanding the radioactive decay rate equation is vital for calculating the age of geological samples. This equation reflects the relationship between the number of radioactive nuclei remaining in a sample and the time that has passed. In mathematical terms, the equation is expressed as:
\[ t = \frac{1}{\text{(lambda)}} \times \text{ln} \left(1 + \frac{N}{N_0}\right) \]
where:
The decay constant ((lambda)) is a key factor in this calculation and is derived from the half-life of the radioactive isotope. To solve radiometric dating problems, we estimate the time elapsed since the formation of the rock by using this decay rate equation, essentially allowing us to 'read' the geological clock of a sample.
\[ t = \frac{1}{\text{(lambda)}} \times \text{ln} \left(1 + \frac{N}{N_0}\right) \]
where:
- is the time that has elapsed,
- is the current number of radioactive atoms,
- is the initial number of radioactive atoms, and
- (lambda) is the decay constant.
The decay constant ((lambda)) is a key factor in this calculation and is derived from the half-life of the radioactive isotope. To solve radiometric dating problems, we estimate the time elapsed since the formation of the rock by using this decay rate equation, essentially allowing us to 'read' the geological clock of a sample.
Potassium-40 Half-Life
The concept of half-life is central to the science of radiometric age dating. It describes the time required for half the quantity of a radioactive isotope to decay. For the particular case of potassium-40, or , it has a significant half-life of
\[ 1.248 \times 10^9 \text{ years} \]
by (beta) decay, and \[ 1.4 \times 10^9 \text{ years} \]
by electron capture. This long half-life makes potassium-40 a valuable isotope for dating ancient geological events.
To make our age determination as accurate as possible, we average the two possible half-lives provided for potassium-40 when calculating the decay constant, considering both modes of decay that the isotope undergoes. It's this reasoned approach that enhances the reliability of the age estimate for the volcanic rock in question.
\[ 1.248 \times 10^9 \text{ years} \]
by (beta) decay, and \[ 1.4 \times 10^9 \text{ years} \]
by electron capture. This long half-life makes potassium-40 a valuable isotope for dating ancient geological events.
To make our age determination as accurate as possible, we average the two possible half-lives provided for potassium-40 when calculating the decay constant, considering both modes of decay that the isotope undergoes. It's this reasoned approach that enhances the reliability of the age estimate for the volcanic rock in question.
Argon-40 to Potassium-40 Mass Ratio
The mass ratio of argon-40 to potassium-40 in a sample is a crucial aspect of radiometric age dating. Argon-40 is a noble gas that is created as a result of the radioactive decay of potassium-40. In a closed system, where no argon is lost to the atmosphere, the accumulation of argon-40 can provide us with important insights into the sample's age.
In your exercise, the provided ratio is
\[ \text{Argon-40} : \text{Potassium-40} = 2.9 \]
This ratio essentially indicates that for every atom of potassium-40 present, there are about 2.9 atoms of argon-40 that have been produced through radioactive decay. By employing the radioactive decay rate equation, this ratio allows us to determine the elapsed time since the volcanic rock solidified and ceased exchanging gases with the environment. Understanding these ratios and how they apply to the decay rate equation is integral to unlocking the history recorded within rocks and other materials.
In your exercise, the provided ratio is
\[ \text{Argon-40} : \text{Potassium-40} = 2.9 \]
This ratio essentially indicates that for every atom of potassium-40 present, there are about 2.9 atoms of argon-40 that have been produced through radioactive decay. By employing the radioactive decay rate equation, this ratio allows us to determine the elapsed time since the volcanic rock solidified and ceased exchanging gases with the environment. Understanding these ratios and how they apply to the decay rate equation is integral to unlocking the history recorded within rocks and other materials.
Other exercises in this chapter
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