Problem 32
Question
Verify the Identity. $$(a \cos t-b \sin t)^{2}+(a \sin t+b \cos t)^{2}=a^{2}+b^{2}$$
Step-by-Step Solution
Verified Answer
The identity is verified; the expressions are equal to \(a^2 + b^2\).
1Step 1: Expand the First Term
Let's expand the first term: \((a \cos t - b \sin t)^2\). This expression can be expanded as follows:\[(a \cos t - b \sin t)^2 = (a \cos t)^2 - 2(a \cos t)(b \sin t) + (b \sin t)^2\]Simplifying, we get:\[a^2 \cos^2 t - 2ab \cos t \sin t + b^2 \sin^2 t\]
2Step 2: Expand the Second Term
Now, let's expand the second term:\((a \sin t + b \cos t)^2\). This expression can be expanded as follows:\[(a \sin t + b \cos t)^2 = (a \sin t)^2 + 2(a \sin t)(b \cos t) + (b \cos t)^2\]Simplifying, we get:\[a^2 \sin^2 t + 2ab \sin t \cos t + b^2 \cos^2 t\]
3Step 3: Combine Both Expanded Terms
Combine both expanded terms from Step 1 and Step 2:\[(a \cos t - b \sin t)^2 + (a \sin t + b \cos t)^2 = a^2 \cos^2 t - 2ab \cos t \sin t + b^2 \sin^2 t + a^2 \sin^2 t + 2ab \sin t \cos t + b^2 \cos^2 t\]Observe that the \(-2ab \cos t \sin t\) and \(+2ab \sin t \cos t\) terms cancel each other out.
4Step 4: Use Pythagorean Identity
After cancellation, we are left with:\[a^2 \cos^2 t + b^2 \sin^2 t + a^2 \sin^2 t + b^2 \cos^2 t\]Let's group the terms:\[a^2 (\cos^2 t + \sin^2 t) + b^2 (\sin^2 t + \cos^2 t)\]Using the Pythagorean identity: \(\cos^2 t + \sin^2 t = 1\), this simplifies to:\[a^2(1) + b^2(1) = a^2 + b^2\]
5Step 5: Conclusion: Verification of Identity
Thus, we have verified that:\[(a \cos t - b \sin t)^2 + (a \sin t + b \cos t)^2 = a^2 + b^2\]This confirms that the given expression is indeed an identity.
Key Concepts
Pythagorean IdentityExpansion of BinomialsVerification of IdentitiesTrigonometric Functions
Pythagorean Identity
The Pythagorean identity is one of the fundamental trigonometric identities. It stems from the basic relationship in a right triangle, where the sum of the squares of the two legs equals the square of the hypotenuse. In trigonometry, this relationship is expressed as:\[\cos^2 t + \sin^2 t = 1\]This identity enables simplification and transformation of trigonometric expressions, like in our exercise, where we switched:
- \(a^2 (\cos^2 t + \sin^2 t)\) into \(a^2 \times 1\), simplifying it to \(a^2\)
- \(b^2 (\sin^2 t + \cos^2 t)\) into \(b^2 \times 1\), simplifying it to \(b^2\)
Expansion of Binomials
The expansion of binomials is a common task in algebra that involves expanding expressions raised to a power. Let's take a binomial of the form \((x + y)^2\). To expand:
- Square the first term: \(x^2\)
- Multiply the two terms together and double the result: \(2xy\)
- Square the second term: \(y^2\)
Verification of Identities
Verification of trigonometric identities involves proving two expressions are equal. To verify, follow these steps:
- Simplify each side of the identity separately.
- Use known identities, such as the Pythagorean identity, to transform terms.
- Cancel identical terms or combine like terms.
- Finally, check if the simplified expressions are the same on both sides.
Trigonometric Functions
Trigonometric functions like sine and cosine are foundational in understanding many mathematical concepts. They describe the relationship between the angles and sides of a right triangle, and are periodic functions with specific properties:
- Sine (\(\sin t\)): Represents the y-coordinate of a point on the unit circle.
- Cosine (\(\cos t\)): Represents the x-coordinate of a point on the unit circle.
- These functions cycle through their values as angles increase, which is useful in modeling periodic phenomena.
Other exercises in this chapter
Problem 32
Complete the statements. (a) As \(x \rightarrow 1^{-}, \sin ^{-1} x \rightarrow\text{____}\) (b) As \(x \rightarrow-1^{+}, \cos ^{-1} x \rightarrow\text{____}\)
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Use sum-to-product formulas to find the solutions of the equation. $$\cos 3 x=-\cos 6 x$$
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Express in terms of the cosine function with exponent 1. \(\cos ^{4} 2 x\)
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Exer. \(25-36:\) Verify the reduction formula. $$\cos \left(\theta-\frac{5 \pi}{2}\right)=\sin \theta$$
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