Problem 32
Question
Use the slope formula to find the slope of the line containing each pair of points. $$(-7,4) \text { and }(1,4)$$
Step-by-Step Solution
Verified Answer
The slope of the line containing the points \((-7,4)\) and \((1,4)\) is 0.
1Step 1: Identify the coordinates of the points
We are given the points \((-7,4)\) and \((1,4)\). Identify the coordinates as follows:
Point 1: \((x1, y1) = (-7, 4)\)
Point 2: \((x2, y2) = (1, 4)\)
2Step 2: Apply the slope formula
Now, apply the slope formula using the identified coordinates. So, we have:
\(m = \frac{y2-y1}{x2-x1}\)
3Step 3: Substitute the coordinates into the formula
Substitute the coordinates from step 1 into the slope formula:
\(m = \frac{4-4}{1-(-7)}\)
4Step 4: Simplify the expression
Simplify the expression to find the slope:
\(m = \frac{0}{8}\)
5Step 5: Calculate the slope
Now, we can compute the slope by dividing the numerator by the denominator:
\(m = 0\)
The slope of the line containing the points \((-7,4)\) and \((1,4)\) is 0.
Key Concepts
Coordinate GeometrySlope FormulaLinear Equations
Coordinate Geometry
In coordinate geometry, we look at shapes and lines in a grid-like setup known as the Cartesian plane. This plane is made from two perpendicular lines named the x-axis and y-axis. Here's where we plot points that have coordinates such as \((-7,4)\) and \(1,4)\).
The coordinates are like directions on the grid:
The coordinates are like directions on the grid:
- The first number of the pair tells us how far along the x-axis (the horizontal line) we move.
- The second number tells us how far up or down the y-axis (the vertical line) we go.
Slope Formula
The slope formula gives us a way to calculate the steepness or tilt of a line. It's like measuring the angle of a hill to see how steep it is. The formula is as follows:
The slope here is \(0\). A zero slope tells us the line is absolutely flat, just like a table. This means no matter where you look along the x-axis, the y-value doesn't change—perfectly horizontal!
- \( m = \frac{\Delta y}{\Delta x} \) which means the change in y-coordinates over the change in x-coordinates.
- Find the difference in y-coordinates: \(4-4 = 0\)
- Find the difference in x-coordinates: \(1 - (-7) = 8\)
The slope here is \(0\). A zero slope tells us the line is absolutely flat, just like a table. This means no matter where you look along the x-axis, the y-value doesn't change—perfectly horizontal!
Linear Equations
Linear equations represent straight lines when graphed on the coordinate plane. They're often written in the format \(y = mx + b\), where:
If both points \((-7,4)\) and \(1,4)\) have a y-coordinate of \(4\), then \(b\), the y-value where the line crosses the y-axis is \(4\). So, the equation of our line is \(y = 4\).
Linear equations help us predict and understand relationships. In this case, it tells us that no matter how far we travel along the x-axis, the y-value remains steady at 4, ensuring a constant level. Linear equations are powerful tools in algebra and beyond.
- \(m\) is the slope of the line.
- \(b\) is the y-intercept, the point where the line crosses the y-axis.
If both points \((-7,4)\) and \(1,4)\) have a y-coordinate of \(4\), then \(b\), the y-value where the line crosses the y-axis is \(4\). So, the equation of our line is \(y = 4\).
Linear equations help us predict and understand relationships. In this case, it tells us that no matter how far we travel along the x-axis, the y-value remains steady at 4, ensuring a constant level. Linear equations are powerful tools in algebra and beyond.
Other exercises in this chapter
Problem 31
Solve each system by substitution. $$\begin{aligned}&\frac{1}{4} x-\frac{1}{2} y=1\\\&\frac{2}{3} x+\frac{1}{6} y=\frac{25}{6}\end{aligned}$$
View solution Problem 32
\(\begin{aligned} 5 x+y-2 z &=-2 \\\\-\frac{1}{2} x-\frac{3}{4} y+2 z &=\frac{5}{4} \\ x-6 z &=3 \end{aligned}\)
View solution Problem 32
Solve each system using the elimination method. $$\begin{array}{l}\frac{x}{12}-\frac{y}{6}=\frac{2}{3} \\\\\frac{x}{4}+\frac{y}{3}=2\end{array}$$
View solution Problem 32
Solve each system by substitution. $$\begin{aligned}&\frac{2}{3} x+\frac{2}{3} y=6\\\&\frac{3}{2} x-\frac{1}{4} y=\frac{13}{2}\end{aligned}$$
View solution