Problem 32
Question
Use the guidelines of this section to sketch the curve. $$y=\sec x+\tan x, \quad 0< x <\pi / 2$$
Step-by-Step Solution
Verified Answer
The curve increases from near 1 at \(x=0\) to infinity as \(x\) approaches \(\frac{\pi}{2}\) with a vertical asymptote there.
1Step 1: Understand the Functions Involved
The function we're dealing with is the sum of the secant and tangent functions, \(y = \sec x + \tan x\). In trigonometry, \(\sec x\) is the reciprocal of \(\cos x\) and \(\tan x\) is \(\frac{{\sin x}}{{\cos x}}\). Both functions have a vertical asymptote at \(x = \frac{\pi}{2}\), which causes them to go to infinity as \(x\) approaches \(\frac{\pi}{2}\) from the left.
2Step 2: Identify the Domain and Behavior
The given domain is \(0 < x < \frac{\pi}{2}\). Both \(\sec x\) and \(\tan x\) are undefined at \(x = \frac{\pi}{2}\), causing a vertical asymptote there. As \(x\) approaches \(\frac{\pi}{2}\) from the left, both \(\sec x\) and \(\tan x\) go to positive infinity.
3Step 3: Consider the Combined Function
The function is \(y = \sec x + \tan x\). For small values of \(x\) close to 0, \(\sec x\) is approximately 1 and \(\tan x\) is approximately \(x\). As \(x\) increases toward \(\frac{\pi}{2}\), both \(\sec x\) and \(\tan x\) increase rapidly, causing \(y\) to also increase rapidly.
4Step 4: Calculate Values at Key Points
Calculate a few values to understand the behavior:- At \(x = \frac{\pi}{6}\), \(\sec(\frac{\pi}{6}) = \frac{2}{\sqrt{3}}\) and \(\tan(\frac{\pi}{6}) = \frac{1}{\sqrt{3}}\).- At \(x = \frac{\pi}{4}\), \(\sec(\frac{\pi}{4}) = \sqrt{2}\) and \(\tan(\frac{\pi}{4}) = 1\).Use these values to sketch a rough plot of the curve behavior.
5Step 5: Sketch the Curve
Based on the calculated points and asymptote, sketch the curve starting near (0, 1) and increasing through the calculated values towards infinity as \(x\) approaches \(\frac{\pi}{2}\). Ensure the plot shows the increase and indicates the vertical asymptote.
Key Concepts
Secant FunctionTangent FunctionCurve Sketching
Secant Function
The secant function, denoted by \( \sec x \), is one of the six fundamental trigonometric functions. It is defined as the reciprocal of the cosine function. In mathematical terms, this means \( \sec x = \frac{1}{\cos x} \). When plotting the secant function, it is important to remember a few key characteristics:
- The secant function is undefined whenever the cosine function is zero, which occurs at odd multiples of \( \frac{\pi}{2} \).
- Due to this, the secant function has vertical asymptotes at those points.
- The function reaches its maximum and minimum values when the cosine is at its maximum and minimum, respectively.
Tangent Function
The tangent function, represented by \( \tan x \), is another basic trigonometric function. It's defined as the ratio of the sine and cosine functions, so \( \tan x = \frac{\sin x}{\cos x} \). Here are some important aspects to consider when dealing with the tangent function:
- It is periodic with a period of \( \pi \).
- The tangent function is undefined where the cosine is zero, similar to the secant function, leading to vertical asymptotes at those points.
- The function traverses from negative to positive infinity across each period without reaching a maximum or minimum bound.
Curve Sketching
Curve sketching involves drawing a graph based on the behavior of a function. When sketching the curve for combined functions like \( y = \sec x + \tan x \), it is important to incorporate the characteristics of each individual function as well as their collective behavior:
- Identify and mark vertical asymptotes and note any undefined points in the domain.
- Understand how each component function behaves on its own. As noted earlier, both \( \sec x \) and \( \tan x \) increase rapidly towards \( \frac{\pi}{2} \).
- Combine these behaviors by calculating the sum at specific key points to determine how the combined function behaves.
Other exercises in this chapter
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