Problem 32
Question
Use the definition of the logarithmic function to find \(x .\) (a) \(\log _{4} 2=x\) (b) \(\log _{4} x=2\)
Step-by-Step Solution
Verified Answer
(a) \(x = \frac{1}{2}\)
(b) \(x = 16\)
1Step 1: Understanding Logarithmic Form
The logarithmic equation \ \(\log_b a = x\ \) implies that \ \(b^x = a\ \). This is the definition of a logarithm, stating that the logarithm of \(a\) with base \(b\) is \(x\), when \(b\) raised to the power of \(x\) equals \(a\).
2Step 2: Solving Part (a)
For equation (a), \(\log_4 2 = x\), we apply the logarithmic definition: \(4^x = 2\). To find \(x\), observe that \(2 = 4^{1/2}\), or equivalently \(2 = (2^2)^{1/2} = 2^{1}\). This simplifies to \(4^{1/2} = 2\), indicating \(x = \frac{1}{2}\).
3Step 3: Solving Part (b)
For equation (b), \(\log_4 x = 2\), we again utilize the logarithmic definition: \(4^2 = x\). Calculating \(4^2\) yields \(16\). Thus, \(x = 16\).
Key Concepts
Exponential FormLogarithm EquationsBase of Logarithm
Exponential Form
Exponential form is a mathematical way of expressing numbers through powers and bases. When you come across something like \(b^x = a\), it means you're dealing with the exponential form. Here, \(b\) is the base and \(x\) is the exponent. The core idea is that the base raised to the power of the exponent equals \(a\). This concept is fundamental not only in understanding logarithms but also in a wide range of mathematical applications, such as solving equations and modeling growth scenarios.
In the context of logarithms, understanding exponential form is crucial. When you have a logarithmic equation like \(\log_b a = x\), it's saying that the base \(b\), when raised to the power \(x\), gives you \(a\).
In the context of logarithms, understanding exponential form is crucial. When you have a logarithmic equation like \(\log_b a = x\), it's saying that the base \(b\), when raised to the power \(x\), gives you \(a\).
- This relationship helps to "unwrap" the log back into its exponential expression.
- This conversion is essential for solving logarithmic equations, as it often makes them much more straightforward to solve.
Logarithm Equations
Logarithm equations are a way to find unknown exponents. They occur when we set two logarithmic expressions equal to one another. The essence of a logarithmic equation is that it lets us work backward from an exponential relationship. For instance, in the problem \(\log_4 2 = x\), our task is to figure out what power the base \(4\) must be raised to, in order to yield \(2\).
To handle logarithm equations:
To handle logarithm equations:
- Convert the logarithmic equation into its corresponding exponential form. For example, converting \(\log_4 2 = x\) gives us \(4^x = 2\).
- Solve the resulting exponential equation. In this case, recognizing that \(2 = 4^{1/2}\) leads directly to \(x = \frac{1}{2}\).
Base of Logarithm
The base of a logarithm is the number that is raised to a power to get another number. It's a crucial part of understanding how logarithms work. In a logarithmic expression like \(\log_b a\), \(b\) is the base. Knowing the base is important, because different bases change how you approach solving the equation.
When dealing with different types of bases:
When dealing with different types of bases:
- If \(b = 10\), it's called a common logarithm, often written simply as \(\log\).
- If \(b = e\) (where \(e\) is the Euler's number, approximately 2.71828), it's a natural logarithm, noted as \(\ln\).
- Specific problems can use bases like 2, which often appear in computer science due to binary systems.
Other exercises in this chapter
Problem 31
Solve the equation. $$e^{4 x}+4 e^{2 x}-21=0$$
View solution Problem 31
Use the Laws of Logarithms to expand the expression. $$\ln \sqrt{a b}$$
View solution Problem 32
These exercises deal with logarithmic scales. The pH reading of a glass of liquid is given. Find the hydrogen ion concentration of the liquid. (a) Beer: \(\math
View solution Problem 32
Solve the equation. $$e^{x}-12 e^{-x}-1=0$$
View solution