Problem 32
Question
Use the concept that \(y=c,-\infty
Step-by-Step Solution
Verified Answer
Yes, the differential equation has a constant solution, specifically \( y = 0 \).
1Step 1: Identify Constant Solution Condition
According to the problem, a constant function is represented as \( y = c \), where \( c \) is a constant. A function is constant if its derivative \( y' = 0 \).
2Step 2: Set the First and Second Derivatives to Zero
For a constant solution \( y = c \), we have \( y' = 0 \) and the second derivative \( y'' = 0 \) as well. Substitute these into the differential equation: \[ x^2 \cdot 0 - 7x \cdot 0 + 15c = 0 \] Simplifying this equation, we get \[ 15c = 0 \].
3Step 3: Solve for Constant Solution
Solving the equation \( 15c = 0 \) gives \( c = 0 \). Therefore, the constant solution to the differential equation is \( y = 0 \).
4Step 4: Conclusion on Constant Solutions
The given differential equation \( x^{2} y^{
ime
ime}-7 x y^{
ime}+15 y=0 \) does possess a constant solution, and it is specifically the function \( y = 0 \).
Key Concepts
Understanding Differential EquationsExploring Constant FunctionsThe Significance of a Zero Derivative
Understanding Differential Equations
Differential equations are mathematical equations that involve derivatives of a function. They describe relationships involving rates of change and are key tools in modeling real-world phenomena. Differential equations are prevalent in fields like physics, engineering, and economics. When you encounter a differential equation, you're dealing with a formula that expresses how a certain quantity changes with respect to another.
In the given exercise, the differential equation is \( x^{2} y'' - 7x y' + 15y = 0 \). This equation is called a second-order linear differential equation because it involves the second derivative of \( y \), designated as \( y'' \). Solving differential equations often involves finding a function or set of functions that satisfy the equation. The solution might vary depending on whether non-constant or constant solutions are considered.
In the given exercise, the differential equation is \( x^{2} y'' - 7x y' + 15y = 0 \). This equation is called a second-order linear differential equation because it involves the second derivative of \( y \), designated as \( y'' \). Solving differential equations often involves finding a function or set of functions that satisfy the equation. The solution might vary depending on whether non-constant or constant solutions are considered.
Exploring Constant Functions
A constant function is one of the simplest forms of a function in mathematics. It is denoted as \( y = c \), where \( c \) is a constant value. This means that no matter the input, the output remains the same, perfectly flat and unchanging over an interval.
- Constant functions have a constant rate of change, explicitly indicating that they do not change!
- Their graphical representation is a horizontal line on a Cartesian plane.
- An example of a constant function would be \( y = 3 \), which is simply represented as a straight line parallel to the x-axis.
The Significance of a Zero Derivative
In calculus, taking the derivative of a function helps to determine how that function changes. When a derivative is zero, \( y' = 0 \), it indicates no change. In other words, the function is stable at that point, operating as a constant function.
For a constant function, both the first derivative \( y' \) and the second derivative \( y'' \) are zero because the function's rate of change does not vary. This characteristic is essential when working with differential equations, as substituting zero derivatives into the equation can reveal whether constant solutions are possible understandings of the setup.
These zero derivatives represent the concept of equilibrium in many applications, signifying a state where forces balance and no net change occurs. This is why identifying and working with zero derivatives are crucial in confirming the existence of constant solutions for differential equations.
For a constant function, both the first derivative \( y' \) and the second derivative \( y'' \) are zero because the function's rate of change does not vary. This characteristic is essential when working with differential equations, as substituting zero derivatives into the equation can reveal whether constant solutions are possible understandings of the setup.
These zero derivatives represent the concept of equilibrium in many applications, signifying a state where forces balance and no net change occurs. This is why identifying and working with zero derivatives are crucial in confirming the existence of constant solutions for differential equations.
Other exercises in this chapter
Problem 31
Use the concept that \(y=c,-\infty
View solution Problem 31
In Problem 31 and 32, verify that the function defined by the definite integral is a particular solution of the given differential equation. In both problems, u
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Use the concept that \(y=c,-\infty
View solution Problem 33
The differential equation \(d P / d t=(k \cos t) P\) where \(k\) is a positive constant, is a model of human population \(P(t)\) of a certain community. Discuss
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