Problem 32
Question
Use interval notation to express solution sets and graph each solution set on a number line. Solve each linear inequality. $$-5 x \leq 30$$
Step-by-Step Solution
Verified Answer
The solution to the inequality is \(x \geq -6\), which can be expressed in interval notation as \([-6, +\infty)\). A graph of this solution on a number line would show a closed circle on -6 and a line extending to the right.
1Step 1: Solve the inequality
Starting with the inequality \(-5x \leq 30\), divide both sides by -5. Remember, since we are dividing by a negative number, the inequality flips to become \(x \geq -6\). That is the solution to the given inequality.
2Step 2: Express the solution in interval notation
We know that \(x\) must be greater than or equal to -6. In interval notation, this is expressed as \([-6, +\infty)\). This means that the solution includes all numbers greater than or equal to -6.
3Step 3: Graph the solution
To graph the solution on a number line, plot a closed circle on -6 (because -6 is included in the solution) and draw a line extending to the right (indicating that the solution includes all numbers greater than -6).
Key Concepts
Interval NotationNumber Line GraphingSolving InequalitiesInequality Properties
Interval Notation
Interval notation is a simple way to represent a range of values in mathematics. When we solve an inequality, like the example \(x \geq -6\), it involves all numbers greater than or equal to -6. This is where interval notation comes in handy.
For the interval notation of our solution:
So, the interval notation \([-6, +\infty)\) represents all numbers from -6 to positive infinity."
For the interval notation of our solution:
- The square bracket \([-6\) indicates that the number -6 is included in the solution set."
- The infinity symbol \(+\infty)\) means the set continues indefinitely in the positive direction."
So, the interval notation \([-6, +\infty)\) represents all numbers from -6 to positive infinity."
Number Line Graphing
Graphing solutions on a number line gives a visual representation of the values that satisfy an inequality. For our inequality solution, \(x \geq -6\), we start with a number line and follow these steps:
Using both interval notation and graphing provides a complete picture of where \(x\) falls in the solution set."
- Mark the point -6 on the number line and draw a closed circle at this point. The closed circle indicates -6 is included in the solution."
- Draw a line extending to the right from -6, signifying that all numbers greater than -6 are part of the solution set."
Using both interval notation and graphing provides a complete picture of where \(x\) falls in the solution set."
Solving Inequalities
Solving inequalities involves similar steps to algebraic equations but with a few unique rules. Let's revisit the inequality in our exercise: \(-5x \leq 30\). Here's how to solve it:
Mastering these mechanics will make solving any linear inequality straightforward."
- We need to isolate \(x\) on one side of the inequality. To do this, we divide both sides by -5."
- Importantly, dividing or multiplying both sides of an inequality by a negative number requires flipping the inequality sign. This transforms \(-5x \leq 30\) into \(x \geq -6\)."
Mastering these mechanics will make solving any linear inequality straightforward."
Inequality Properties
Understanding the properties and rules of inequalities is essential to solving them correctly. When working with inequalities, particularly note these properties:
By keeping these properties in mind, you’ll be able to tackle each problem methodically."
- **Transitive Property**: If \(a > b\) and \(b > c\), then \(a > c\)."
- **Addition/Subtraction**: You can add or subtract the same number on both sides without altering the inequality."
- **Multiplication/Division by Positives**: Multiplying or dividing both sides by a positive number keeps the inequality direction the same."
- **Multiplication/Division by Negatives**: Multiplying or dividing both sides by a negative number flips the inequality sign, as seen in our exercise."
By keeping these properties in mind, you’ll be able to tackle each problem methodically."
Other exercises in this chapter
Problem 32
In Exercises \(29-44\), perform the indicated operations and write the result in standard form. $$ 5 \sqrt{-8}+3 \sqrt{-18} $$
View solution Problem 32
Solve each equation in Exercises \(15-34\) by the square root property. $$ (8 x-3)^{2}=5 $$
View solution Problem 32
Solve each equation with rational exponents. Check all proposed solutions. $$ x^{\frac{3}{2}}=27 $$
View solution Problem 32
Contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These a
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