Problem 32
Question
Use a calculator to evaluate each expression. \({ }_{32} C_{4}\)
Step-by-Step Solution
Verified Answer
The result of \( _{32}C_4 \) is 35,960.
1Step 1: Understand the Combination Formula
The combination formula is used to determine the number of ways to choose a subset of items from a larger set, without regard to the order of selection. It is given by the expression \[ _nC_k = \frac{n!}{k!(n-k)!} \] where \( n \) is the total number of items, and \( k \) is the number of items to choose. In this problem, \( n = 32 \) and \( k = 4 \).
2Step 2: Calculate the Factorials
We need to calculate the factorials in the formula: \( n! = 32! \), \( k! = 4! \), and \( (n-k)! = 28! \). Factorial of a number \( n \) is the product of all positive integers less than or equal to \( n \).
3Step 3: Plug Values into the Formula
Now substitute the calculated factorials into the combination formula:\[ _{32}C_4 = \frac{32!}{4!\cdot 28!} \]
4Step 4: Simplify the Expression Using a Calculator
Using a calculator, compute the expression. We note that \( 32! \) over \( 28! \) simplifies as \( 32 \times 31 \times 30 \times 29 \), because the terms in \( 28! \) cancel out, leaving us with the expression: \[ \frac{32 \times 31 \times 30 \times 29}{4!} = \frac{32 \times 31 \times 30 \times 29}{24} \]
5Step 5: Compute the Final Result
Using a calculator, evaluate the above expression:\[ _{32}C_4 = \frac{32 \times 31 \times 30 \times 29}{24} = 35,960 \]
Key Concepts
FactorialsCombination FormulaCalculator Use
Factorials
A factorial is a mathematical operation that is used in many areas, including combinations and permutations. The factorial of a positive integer \( n \), denoted \( n! \), is the product of all positive integers up to \( n \).
For example:
For example:
- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 1! = 1 \) (by convention)
- \( 0! = 1 \) (also by convention)
Combination Formula
The combination formula is a useful tool in probability and statistics to determine how many different groups or subsets can be formed from a larger set of distinct items. It is given by the expression
\[ _nC_k = \frac{n!}{k!(n-k)!} \] where:
This formula ensures that there is no repetition, and the order of selection does not matter, focusing solely on the unique combinations possible.
\[ _nC_k = \frac{n!}{k!(n-k)!} \] where:
- \( n \) is the total number of items.
- \( k \) is the number of items to choose.
This formula ensures that there is no repetition, and the order of selection does not matter, focusing solely on the unique combinations possible.
Calculator Use
Using calculators in combination problems streamlines the process and avoids errors in manual calculations, especially when dealing with large numbers. To evaluate a combination like \({ }_{32}C_{4}\), you should first understand that you will need to compute factorials where needed.
A good calculator will have at least a factorial function, often labeled as "n!". Here’s how you can simplify using a calculator:
A good calculator will have at least a factorial function, often labeled as "n!". Here’s how you can simplify using a calculator:
- Calculate \( 32! \) and \( 28! \). Once you have those, you can focus on the terms \( 32 \times 31 \times 30 \times 29 \) by realizing that \( \frac{32!}{28!} \) equals that product.
- Input these numbers directly into the calculator to find \( 4! \), which is 24.
- Finally, compute \( \frac{32 \times 31 \times 30 \times 29}{24} \) to find \( _{32}C_4 = 35,960 \).
Other exercises in this chapter
Problem 32
Prove each statement by mathematical induction. \(2^{n}>n^{2},\) for \(n>4\)
View solution Problem 32
Find \(a_{1}\) for each arithmetic sequence. $$S_{28}=2926, a_{28}=199$$
View solution Problem 32
Write the binomial expansion for each expression. $$(4 a-5 b)^{5}$$
View solution Problem 32
Use a formula to find the sum of each series. $$\sum_{i=1}^{4} 2^{i}$$
View solution