Problem 32
Question
Two skaters collide and grab on to each other on frictionless ice. One of them, of mass \(70.0 \mathrm{kg},\) is moving to the right at \(2.00 \mathrm{m} / \mathrm{s},\) while the other, of mass \(65.0 \mathrm{kg},\) is moving to the left at 2.50 m/s. What are the magnitude and direction of the velocity of these skaters just after they collide?
Step-by-Step Solution
Verified Answer
The skaters move to the left at a velocity of 0.167 m/s.
1Step 1: Understand the Conservation of Momentum
In this problem, we need to use the principle of conservation of momentum. Momentum is conserved in isolated systems, which means the total momentum before the collision is equal to the total momentum after the collision. This principle is crucial as there is no external force applied here.
2Step 2: Identify the Initial Momenta
First, calculate the initial momentum of each skater. The formula for momentum is given by \( p = mv \), where \( m \) is mass and \( v \) is velocity.- The initial momentum of the 70 kg skater: \( p_1 = 70 \, \text{kg} \, \times \, 2.00 \, \text{m/s} = 140 \, \text{kg m/s} \).- The initial momentum of the 65 kg skater: \( p_2 = 65 \, \text{kg} \, \times \, (-2.50) \, \text{m/s} = -162.5 \, \text{kg m/s} \) (the negative sign indicates direction).
3Step 3: Calculate Total Initial Momentum
Add the two momenta to get the total initial momentum: \( P_{\text{total initial}} = 140 \, \text{kg m/s} + (-162.5 \, \text{kg m/s}) = -22.5 \, \text{kg m/s} \).
4Step 4: Determine Total System Mass
The total mass of the system after the skaters collide is the sum of the two individual masses: \( M_{\text{total}} = 70 \, \text{kg} + 65 \, \text{kg} = 135 \, \text{kg} \).
5Step 5: Apply Conservation of Momentum
According to the conservation of momentum, \( P_{\text{total initial}} = P_{\text{total final}} \). Since \( P_{\text{total final}} = M_{\text{total}} \times v_{\text{after}} \), we substitute this into the equation: \(-22.5 \, \text{kg m/s} = 135 \, \text{kg} \times v_{\text{after}} \).
6Step 6: Solve for Final Velocity
Solve the equation for the velocity \( v_{\text{after}} \):\[ v_{\text{after}} = \frac{-22.5 \, \text{kg m/s}}{135 \, \text{kg}} = -0.167 \, \text{m/s} \].The negative sign indicates that the direction of the velocity is to the left.
Key Concepts
MomentumElastic CollisionSystem MassVelocity Calculation
Momentum
Momentum is a fundamental concept in physics that describes the motion of an object. It is defined as the product of an object's mass and velocity, usually expressed in the formula:
Momentum is vector-based, meaning the direction of the velocity affects the sign (positive or negative) of the momentum. By considering both direction and magnitude, we can accurately assess the motion in any collision scenario.
- \( p = m \cdot v \)
- Where \( p \) is the momentum, \( m \) is the mass, and \( v \) is the velocity of the object.
Momentum is vector-based, meaning the direction of the velocity affects the sign (positive or negative) of the momentum. By considering both direction and magnitude, we can accurately assess the motion in any collision scenario.
Elastic Collision
Elastic collisions are special types of collisions where the total kinetic energy and total momentum of the system are both conserved. Although the skaters in this example stick together post-collision, making it a perfectly inelastic collision,
understanding elastic collisions provides a base understanding of how momentum works in general.
If the skaters had rebounded off one another instead of sticking together, we would need to ensure that their total momentum both before and after the collision stayed the same, alongside their kinetic energy. This principle helps us better understand the mechanics behind momentum conservation in various scenarios.
understanding elastic collisions provides a base understanding of how momentum works in general.
If the skaters had rebounded off one another instead of sticking together, we would need to ensure that their total momentum both before and after the collision stayed the same, alongside their kinetic energy. This principle helps us better understand the mechanics behind momentum conservation in various scenarios.
System Mass
The system mass refers to the total combined mass of all objects involved in a situation. In the context of our skater problem, the system mass is simply the sum of the masses of both skaters:
This plays a pivotal role in calculating the final velocity of the system based on momentum conservation.
- First skater's mass: 70 kg
- Second skater's mass: 65 kg
- Total system mass: \( 70 + 65 = 135 \) kg
This plays a pivotal role in calculating the final velocity of the system based on momentum conservation.
Velocity Calculation
In momentum problems, velocity calculation often follows the application of the conservation of momentum principle. For the skaters, the velocity after the collision can be calculated using their combined momentum:
This calculation demonstrates the importance of understanding both direction and magnitude in evaluating post-collision conditions.
- Total initial momentum: \(-22.5 \) kg m/s
- Total system mass: 135 kg
- Formula: \( v_{\text{after}} = \frac{\text{Total Initial Momentum}}{\text{Total Mass}} \)
This calculation demonstrates the importance of understanding both direction and magnitude in evaluating post-collision conditions.
Other exercises in this chapter
Problem 29
Changing Mass. An open-topped freight car with mass \(24,000 \mathrm{kg}\) is coasting without friction along a level track. It is raining very hard, and the ra
View solution Problem 30
An astronaut in space cannot use a conventional means, such as a scale or balance, to determine the mass of an object. But she does have devices to measure dist
View solution Problem 33
A 15.0 -kg fish swimming at 1.10 \(\mathrm{m} / \mathrm{s}\) suddenly gobbles up a 4.50 -kg fish that is initially stationary. Neglect any drag effects of the w
View solution Problem 34
Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. One of them, of mass \(7.50 \mathrm{kg},\) is slidin
View solution