Problem 32
Question
Solve using the square root property. Simplify all radicals. $$ w^{2}=0.49 $$
Step-by-Step Solution
Verified Answer
The solutions are \( w = 0.7 \) and \( w = -0.7 \).
1Step 1: Write the equation
The given equation is \[ w^2 = 0.49 \]. The goal is to solve for \( w \).
2Step 2: Apply the Square Root Property
According to the square root property, if \( w^2 = c \), then \( w = \pm \sqrt{c} \). Applying it to the given equation: \[ w = \pm \sqrt{0.49} \].
3Step 3: Simplify the Square Root
Solve for \( \sqrt{0.49} \). Since \( 0.49 = \(0.7\)^2 \), we find that \[ \sqrt{0.49} = 0.7 \].
4Step 4: Find the Solutions
Considering the positive and negative roots, the solutions are \[ w = \pm 0.7 \].
Key Concepts
Solving Quadratic EquationsSimplifying RadicalsPositive and Negative Roots
Solving Quadratic Equations
When you encounter a quadratic equation of the form \( w^2 = c \), your primary goal is to solve for the variable, in this case, \( w \). The Square Root Property is a powerful tool for these types of equations. Here’s how it works:
According to the Square Root Property, if you have an equation like \( w^2 = c \), then \( w = \pm \sqrt{c} \). Notice the \( \pm \) symbol; it signifies both the positive and negative roots of the square root.
Let’s apply this to our given equation, \( w^2 = 0.49 \). By applying the Square Root Property, we get:
\( w = \pm \sqrt{0.49} \).
This step helps break down the equation so we can move on to simplifying the square root.
According to the Square Root Property, if you have an equation like \( w^2 = c \), then \( w = \pm \sqrt{c} \). Notice the \( \pm \) symbol; it signifies both the positive and negative roots of the square root.
Let’s apply this to our given equation, \( w^2 = 0.49 \). By applying the Square Root Property, we get:
\( w = \pm \sqrt{0.49} \).
This step helps break down the equation so we can move on to simplifying the square root.
Simplifying Radicals
Simplifying radicals is the next crucial step. In our example, we need to simplify \( \sqrt{0.49} \). This simplification involves finding out what number multiplied by itself gives you 0.49.
By recognizing that \( 0.49 = (0.7)^2 \), we know that:
\( \sqrt{0.49} = 0.7 \).
Here’s a pro tip: if the number under the square root is a perfect square, like 0.49 (also 7 times 7), it makes our job easier. Simplified roots lead to simpler answers, which brings us to our final solutions.
By recognizing that \( 0.49 = (0.7)^2 \), we know that:
\( \sqrt{0.49} = 0.7 \).
Here’s a pro tip: if the number under the square root is a perfect square, like 0.49 (also 7 times 7), it makes our job easier. Simplified roots lead to simpler answers, which brings us to our final solutions.
Positive and Negative Roots
When we solve quadratic equations using the Square Root Property, we always consider both positive and negative roots. This is represented by the \( \pm \) symbol.
In our example, after simplifying \( \sqrt{0.49} = 0.7 \), the final solutions are:
\( w = \pm 0.7 \), meaning \( w = 0.7 \) and \( w = -0.7 \).
Why do we consider both roots? Because a negative number squared also results in a positive number (for example, \( (-0.7)^2 = 0.49 \)).
Therefore, it’s essential to include both the positive and negative solutions every time you solve a quadratic equation by using the square root property.
In our example, after simplifying \( \sqrt{0.49} = 0.7 \), the final solutions are:
\( w = \pm 0.7 \), meaning \( w = 0.7 \) and \( w = -0.7 \).
Why do we consider both roots? Because a negative number squared also results in a positive number (for example, \( (-0.7)^2 = 0.49 \)).
Therefore, it’s essential to include both the positive and negative solutions every time you solve a quadratic equation by using the square root property.
Other exercises in this chapter
Problem 31
Solve each problem. Round answers to the nearest tenth as needed. The distance from Jackson to Lodi is about \(40 \mathrm{mi}\), as is the distance from Lodi to
View solution Problem 31
Solve each problem. When appropriate, round answers to the nearest tenth. Two ships leave port at the same time, one heading due south and the other heading due
View solution Problem 32
Graph each parabola. Give the vertex, axis of symmetry, domain, and range. $$ f(x)=-2 x^{2}+12 x-13 $$
View solution Problem 32
Solve each problem. Round answers to the nearest tenth as needed. Medicine Hat and Cranbrook are \(300 \mathrm{~km}\) apart. Steve rides his Harley \(20 \mathrm
View solution