Problem 32
Question
Solve the linear inequality. Express the solution using interval notation and graph the solution set. $$-3 \leq 3 x+7 \leq \frac{1}{2}$$
Step-by-Step Solution
Verified Answer
The solution is \([-\frac{10}{3}, -\frac{13}{6}]\) and is graphed with a shaded segment between these points.
1Step 1: Break Down the Compound Inequality
The given inequality is a compound inequality: \[-3 \leq 3x + 7 \leq \frac{1}{2}\] We need to solve this as two separate inequalities: 1. \(-3 \leq 3x + 7\)2. \(3x + 7 \leq \frac{1}{2}\).
2Step 2: Solve the First Inequality
Solve the inequality \(-3 \leq 3x + 7\):Subtract 7 from both sides:\[-3 - 7 \leq 3x\]\[-10 \leq 3x\]Divide both sides by 3:\[-\frac{10}{3} \leq x\].
3Step 3: Solve the Second Inequality
Solve the inequality \(3x + 7 \leq \frac{1}{2}\):Subtract 7 from both sides:\[3x \leq \frac{1}{2} - 7\]\[3x \leq \frac{1}{2} - \frac{14}{2}\]\[3x \leq -\frac{13}{2}\]Divide both sides by 3:\[x \leq -\frac{13}{6}\].
4Step 4: Combine the Solutions
Combine the results from Steps 2 and 3:\[-\frac{10}{3} \leq x \leq -\frac{13}{6}\].
5Step 5: Express the Solution in Interval Notation
The solution in interval notation is:\[\left[-\frac{10}{3}, -\frac{13}{6}\right]\]
6Step 6: Graph the Solution Set
Draw a number line. Shade the region between \(-\frac{10}{3}\) and \(-\frac{13}{6}\). Both endpoints are included, so represent them with solid dots.
Key Concepts
Compound InequalitiesInterval NotationGraphing Inequalities
Compound Inequalities
Compound inequalities are combinations of two individual inequalities joined by the word "and" or "or." These inequalities describe a range of values that satisfy both conditions. In our problem, we have a compound inequality: \[-3 \leq 3x + 7 \leq \frac{1}{2}\].This can be split into two separate inequalities:
- \(-3 \leq 3x + 7\)
- \(3x + 7 \leq \frac{1}{2}\)
- "And" indicates that solutions must satisfy both inequalities simultaneously.
- "Or" would mean solutions can satisfy either of the inequalities independently.
Interval Notation
Interval notation is a system used to represent a range of numbers along a number line. It is concise and easy to understand. After solving a compound inequality, you express the solution in interval notation. For our inequality, \[-\frac{10}{3} \leq x \leq -\frac{13}{6}\],we need to represent this solution using interval notation. In interval notation:
- Square brackets \([\,]\) denote that an endpoint is included in the solution (i.e., the endpoint satisfies the inequality).
- Parentheses \((\,)\) would denote that an endpoint is not included.
Graphing Inequalities
Graphing inequalities is a visual method to represent the solutions of an inequality on a number line. This not only helps in understanding the solution but also provides a quick way to verify our work. Once we have the solution in interval notation, \(\left[-\frac{10}{3}, -\frac{13}{6}\right]\),we can draw it on a number line:
- Draw a horizontal line representing the number line.
- Mark the points \(-\frac{10}{3}\) and \(-\frac{13}{6}\) on this line.
- Since both endpoints are included in the solution, use solid dots to represent them.
- Shade the region between \(-\frac{10}{3}\) and \(-\frac{13}{6}\) to show all the possible values \(x\) can take.
Other exercises in this chapter
Problem 32
Place the correct symbol \((, \text { or }=)\) in the space. \(\begin{array}{llllll}\text { (a) } \frac{2}{3} & 0.67 & \text { (b) } \frac{2}{3} & -0.67 & \text
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Simplify the expression. $$\sqrt[4]{48}-\sqrt[4]{3}$$
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Find an equation of the line that satisfies the given conditions. \(y\) -intercept \(6 ; \quad\) parallel to the line \(2 x+3 y+4=0\)
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Sketch the region given by the set. $$\\{(x, y)|| x | \leq 2 \text { and }|y| \leq 3\\}$$
View solution