Problem 32
Question
Solve the inequality. Express the answer using interval notation. $$ \left|\frac{x+1}{2}\right| \geq 4 $$
Step-by-Step Solution
Verified Answer
The solution is \((-\infty, -9] \cup [7, \infty)\).
1Step 1: Understand the Absolute Value Inequality
The inequality is \( \left|\frac{x+1}{2}\right| \geq 4 \). An absolute value inequality of the form \(|A| \ge B\) can be rewritten as two inequalities: \(A \geq B\) and \(A \leq -B\). In this case, \(A = \frac{x+1}{2}\) and \(B=4\).
2Step 2: Set Up the Two Inequalities
According to the rule for absolute value inequalities, we set up the conditions: 1. \(\frac{x+1}{2} \geq 4\) 2. \(\frac{x+1}{2} \leq -4\)
3Step 3: Solve the First Inequality
Solve \(\frac{x+1}{2} \geq 4\): Multiply both sides by 2 to eliminate the fraction: \(x+1 \geq 8\) Subtract 1 from both sides: \(x \geq 7\).
4Step 4: Solve the Second Inequality
Solve \(\frac{x+1}{2} \leq -4\): Multiply both sides by 2: \(x+1 \leq -8\) Subtract 1 from both sides: \(x \leq -9\).
5Step 5: Combine the Solutions
The solution to the original inequality \(\left|\frac{x+1}{2}\right| \geq 4\) is the union of the solutions from the two inequalities: \(x \geq 7\) or \(x \leq -9\).
6Step 6: Express the Solution in Interval Notation
The solution, formed by the union of the two intervals, is: \((-\infty, -9] \cup [7, \infty)\).
Key Concepts
Interval NotationInequality SolvingAbsolute Value Properties
Interval Notation
Interval notation is a way of writing subsets of the real number line. In mathematics, we often use this notation to represent the solution sets of inequalities. Depending on the type of inequality, the interval can be open, closed, or half-open. In an interval:
- Round brackets, \((a, b)\), denote an open interval where endpoints \(a\) and \(b\) are not included.
- Square brackets, \([a, b]\), denote a closed interval where endpoints are included.
- Mixing the brackets like \((a, b]\) or \([a, b)\) denotes a half-open interval.
Inequality Solving
Solving inequalities is similar to solving equations, but with an additional focus on maintaining the inequality direction.
- For \( \frac{x+1}{2} \geq 4\), multiplying gives \(x+1 \geq 8\).- Subtracting 1 from both sides yields \(x \geq 7\).- For \( \frac{x+1}{2} \leq -4\), similarly, multiplication leads to \(x+1 \leq -8\) and subtracting 1 results in \(x \leq -9\).These steps help in isolating the variable and solving each component inequality.
- When multiplying or dividing both sides by a negative number, remember to flip the inequality sign.
- Perform arithmetic operations on both sides like addition or subtraction to isolate the variable.
- For \( \frac{x+1}{2} \geq 4\), multiplying gives \(x+1 \geq 8\).- Subtracting 1 from both sides yields \(x \geq 7\).- For \( \frac{x+1}{2} \leq -4\), similarly, multiplication leads to \(x+1 \leq -8\) and subtracting 1 results in \(x \leq -9\).These steps help in isolating the variable and solving each component inequality.
Absolute Value Properties
Absolute value describes the distance of a number from zero on the number line, always being non-negative. Understanding properties of absolute value helps in solving related inequalities. There are specific approaches to handle inequalities with absolute values:
- For \(|A| \ge B\), it means \(A \ge B\) or \(A \le -B\).
- For \(|A| \le B\), it translates to \(-B \le A \le B\).
Other exercises in this chapter
Problem 31
Find all real solutions of the equation. \(x^{2}+3 x+1=0\)
View solution Problem 31
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ \frac{2}{x}-5=\frac{6}{x}+4 $$
View solution Problem 32
\(9-32\) me solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ -\frac{1}{2} \leq \frac{4-3 x}{5} \leq \fra
View solution Problem 32
Evaluate the expression and write the result in the form \(a+b i .\) $$ \frac{25}{4-3 i} $$
View solution