Problem 32
Question
Solve each system by elimination. $$\begin{array}{r}5 x+7 y=6 \\\10 x-3 y=46\end{array}$$
Step-by-Step Solution
Verified Answer
The solution is \(x = 4\) and \(y = -2\).
1Step 1: Align Equations
Write the system of equations in a column format for clarity:1. \(5x + 7y = 6\)2. \(10x - 3y = 46\).
2Step 2: Equalize Coefficients of x
Multiply the first equation by 2 so that the coefficients of \(x\) in both equations match:\[2(5x + 7y) = 2(6)\]This gives us the new equation:\(10x + 14y = 12\).
3Step 3: Subtract Equations to Eliminate x
Subtract the second equation from this new equation to eliminate \(x\):\[(10x + 14y) - (10x - 3y) = 12 - 46 \]Resulting in:\(17y = -34\).
4Step 4: Solve for y
Divide both sides of the equation \(17y = -34\) by 17 to solve for \(y\):\[y = \frac{-34}{17} = -2\].
5Step 5: Substitute y back into one of the original equations
Use \(y = -2\) in the first original equation \(5x + 7y = 6\):\[5x + 7(-2) = 6\]Simplify to find \(x\):\[5x - 14 = 6\].
6Step 6: Solve for x
Add 14 to both sides to isolate \(5x\):\[5x = 20\]Then divide by 5:\[x = \frac{20}{5} = 4\].
7Step 7: Solution
The solution to the system of equations is \(x = 4\) and \(y = -2\).
Key Concepts
Elimination MethodAlgebraSolving Equations
Elimination Method
The elimination method is a popular technique used to solve systems of equations. Its primary goal is to eliminate one variable so that you can easily solve for the other. Using this method involves combining equations strategically. You can do this by either addition or subtraction once the coefficients of the variables are aligned.
Here's a quick recap:
Here's a quick recap:
- Align Equations: Start by writing the system in a column format. This helps you visually track the coefficients and corresponding terms.
- Matching Coefficients: Adjust the coefficients of one variable so they match, letting you eliminate it by subtraction or addition.
- Eliminate and Solve: Once a variable is eliminated, solve the resulting simple equation for the remaining variable.
Algebra
Algebra is the branch of mathematics that deals with symbols and the rules for manipulating those symbols. It's foundational in high school mathematics and involves working with equations, like our system of equations exercise.
In a system of equations:
In a system of equations:
- Expressions: Algebra involves expressions that can include constants, variables, and operations (like plus or minus).
- Equations: Equations are statements of equality with expressions on both sides. Solving them involves finding the values for variables that satisfy this equality.
- Manipulations: Algebra teaches us how to rearrange and simplify these expressions, making the unknown variables easier to solve for.
Solving Equations
Solving equations is a vital skill, and one of the core concepts in algebra. It allows you to find the unknown values that make an equation true. Here's a breakdown of the process as demonstrated in our exercise:
- Transforming Equations: Begin by transforming equations by multiplying or adding to align terms. This makes them easier to handle.
- Isolating Variables: Use strategic operations to isolate the variable. This might involve adding, subtracting, multiplying, or dividing both sides by the same number.
- Substitution: Once you solve for one variable, substitute it into another equation. This leads you to solve for the remaining variable.
Other exercises in this chapter
Problem 31
Perform each operation if possible. $$3\left[\begin{array}{rrr} 6 & -1 & 4 \\ 2 & 8 & -3 \\ -4 & 5 & 6 \end{array}\right]+5\left[\begin{array}{rrr} -2 & -8 & -6
View solution Problem 31
Solve each determinant equation for \(x\). $$\operatorname{det}\left[\begin{array}{rrr}4 & 3 & 0 \\\2 & 0 & 1 \\\\-3 & x & -1\end{array}\right]=5$$
View solution Problem 32
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{array}{c} x+2 y=5 \\ 2 x+y=-
View solution Problem 32
For each matrix, find \(A^{-1}\) if it exists. $$A=\left[\begin{array}{ll} \frac{2}{3} & 0.7 \\ 22 & \sqrt{3} \end{array}\right]$$
View solution