Problem 32
Question
Solve each inequality. Write each answer using solution set notation. $$ -11>x+4 $$
Step-by-Step Solution
Verified Answer
The solution set is \(\{x \mid x < -15\}\).
1Step 1: Isolate the variable
To solve the inequality \(-11 > x + 4\),we need to get \(x\) by itself on one side of the inequality. Start by subtracting \(4\) from both sides of the inequality. \(-11 - 4 > x + 4 - 4\).This simplifies to \(-15 > x\).
2Step 2: Write the solution in set notation
Once the inequality is solved, we translate it into solution set notation. The inequality \(-15 > x\)means that \(x\) can take any value less than \(-15\). In set notation, this is written as:\(\{x \mid x < -15\}\).
Key Concepts
Understanding Solution Set NotationMastering the Art of Solving InequalitiesNavigating Algebraic Manipulation for Inequality Solving
Understanding Solution Set Notation
Understanding solution set notation is a handy way to express which numbers satisfy an inequality. After solving an inequality, it's important to translate your answer into this notation.
Solution set notation is specifically designed to show all possible solutions.
In our example, once we solved the inequality \[-15 > x\]we interpreted it as "all values of \(x\) are less than \(-15\)."This is expressed in solution set notation as:
By using solution set notation, you clearly communicate the range of possible values that satisfy your inequality.
This makes it easier to understand the possible values for \(x\) at a glance.
Solution set notation is specifically designed to show all possible solutions.
In our example, once we solved the inequality \[-15 > x\]we interpreted it as "all values of \(x\) are less than \(-15\)."This is expressed in solution set notation as:
- \(\{x \mid x < -15\}\)
By using solution set notation, you clearly communicate the range of possible values that satisfy your inequality.
This makes it easier to understand the possible values for \(x\) at a glance.
Mastering the Art of Solving Inequalities
Solving inequalities involves finding all possible values that make the inequality true.
This process is quite similar to solving equations, but it has special rules.
For the inequality \(-11 > x + 4\), we aimed to isolate \(x\).We did this by subtracting 4 from both sides, leading to \(-15 > x\).Here are the key steps to remember when solving inequalities:
By understanding these, you can tackle any inequality with confidence!
This process is quite similar to solving equations, but it has special rules.
For the inequality \(-11 > x + 4\), we aimed to isolate \(x\).We did this by subtracting 4 from both sides, leading to \(-15 > x\).Here are the key steps to remember when solving inequalities:
- Perform the same operation on both sides of the inequality, just like in an equation.
- Always be careful when multiplying or dividing by negative numbers. This will reverse the inequality symbol.
By understanding these, you can tackle any inequality with confidence!
Navigating Algebraic Manipulation for Inequality Solving
Algebraic manipulation is the heart of solving inequalities. It's about using mathematical operations to simplify and solve equations or inequalities.
In the exercise \(-11 > x + 4\), we used subtraction to isolate the variable\(x\).We subtracted 4 from both sides, resulting in \(-15 > x\).Understanding these basic steps helps you manage more complex inequalities:
Mastering algebraic manipulation ensures you can confidently navigate through inequalities, whether simple or complex.
In the exercise \(-11 > x + 4\), we used subtraction to isolate the variable\(x\).We subtracted 4 from both sides, resulting in \(-15 > x\).Understanding these basic steps helps you manage more complex inequalities:
- Use addition, subtraction, multiplication, or division as needed to get the variable by itself.
- Keep equations balanced—whatever you do to one side, do to the other.
Mastering algebraic manipulation ensures you can confidently navigate through inequalities, whether simple or complex.
Other exercises in this chapter
Problem 31
Convert Nome, Alaska's \(14^{\circ} \mathrm{F}\) high temperature to Celsius.
View solution Problem 32
The room numbers of two adjacent classrooms are two consecutive even numbers. If their sum is 654 , find the classroom numbers.
View solution Problem 32
Solve. If needed, round money amounts to two decimal places and all other amounts to one decimal place. The number 42 is what percent of \(35 ?\)
View solution Problem 32
Convert Paris, France's low temperature of \(-5^{\circ} \mathrm{C}\) to Fahrenheit.
View solution