Problem 32
Question
Solve each equation and check your proposed solution in Exercises. Begin your work by rewriting each equation without fractions. $$\frac{x}{2}+13=-22$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x=-70\).
1Step 1: Removing the Fraction
Start by multiplying every term by 2 to get rid of the fraction in the equation. Doing this, the equation becomes \(2*(x/2)+2*13=2*-22\), which simplifies to \(x+26=-44\).
2Step 2: Solve for the Variable
Next, isolate x by subtracting 26 from both sides of the equation. This gives the equation: \(x=-44-26\).
3Step 3: Simplify Equation
Simplify the right side of the equation to find the solution to x, which is -70.
4Step 4: Check the Solution
Substitute x=-70 back into the original equation to confirm the solution. The left side of the equation will become \( \(-70/2)+13\), which is -22. As this is equal to the right side of the original equation, the solution is verified to be correct.
Key Concepts
Understanding Fractional EquationsHow to Isolate the Variable in an EquationVerifying Algebraic Solutions
Understanding Fractional Equations
Fractional equations are algebraic expressions that include fractions. To solve these, one common method is to eliminate the fractions as the first step. This is often done by finding the least common denominator (LCD) of all the fractions involved and multiplying each term of the equation by this LCD.
For example, in the equation \(\frac{x}{2}+13=-22\), the only fraction has a denominator of 2. Thus, by multiplying every term by 2, we easily get rid of the fractional part converting it into a simpler linear equation. This helps to avoid mistakes with fractions as we proceed to find the value of the variable.
For example, in the equation \(\frac{x}{2}+13=-22\), the only fraction has a denominator of 2. Thus, by multiplying every term by 2, we easily get rid of the fractional part converting it into a simpler linear equation. This helps to avoid mistakes with fractions as we proceed to find the value of the variable.
How to Isolate the Variable in an Equation
Once you've eliminated fractions, the next step in solving an equation is to isolate the variable. This means moving all terms with the variable to one side of the equation and all the constant terms to the other side.
In the equation \(x + 26 = -44\), we want to isolate \(x\) by getting rid of the constant term attached to it. This is done by performing the inverse operation. Since 26 is added to \(x\), we subtract 26 from both sides resulting in \(x = -44 - 26\).
Isolating the variable is a critical step which makes it easier to see the solution clearly. It is essentially undoing everything that is being done to the variable until it stands alone.
In the equation \(x + 26 = -44\), we want to isolate \(x\) by getting rid of the constant term attached to it. This is done by performing the inverse operation. Since 26 is added to \(x\), we subtract 26 from both sides resulting in \(x = -44 - 26\).
Isolating the variable is a critical step which makes it easier to see the solution clearly. It is essentially undoing everything that is being done to the variable until it stands alone.
Verifying Algebraic Solutions
The final and often overlooked step in solving algebraic equations is to verify the solution. This step is critical to ensure that the solution is correct.
To verify a solution, simply substitute the value of the variable back into the original equation. In our example, we substitute \(x = -70\) back into the original equation \(\frac{x}{2} + 13 = -22\). If the left-hand side simplifies to -22, which matches the right-hand side, we have confirmed that -70 is indeed the solution.
Verification not only confirms the correctness of our solution but also helps students to understand the importance of checking their work. It's crucial to form this as a regular habit in problem-solving.
To verify a solution, simply substitute the value of the variable back into the original equation. In our example, we substitute \(x = -70\) back into the original equation \(\frac{x}{2} + 13 = -22\). If the left-hand side simplifies to -22, which matches the right-hand side, we have confirmed that -70 is indeed the solution.
Verification not only confirms the correctness of our solution but also helps students to understand the importance of checking their work. It's crucial to form this as a regular habit in problem-solving.
Other exercises in this chapter
Problem 32
Solve each equation in using both the addition and multiplication properties of equality. Check proposed solutions. $$3 x-2=9$$
View solution Problem 32
Use the percent formula, \(A=P B: A\) is \(P\) percent of \(B,\) to solve. 8 is \(40 \%\) of what?
View solution Problem 33
A rectangular field is four times as long as it is wide. If the perimeter of the field is 500 yards, what are the field's dimensions?
View solution Problem 33
Solve each equation using the addition property of equality. Be sure to check your proposed solutions. $$x+\frac{3}{4}=-\frac{9}{2}$$
View solution