Problem 32
Question
Solve. $$ 125^{x-2}=25 $$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{8}{3}\).
1Step 1: Express the Equation in Terms of Powers of 5
We start by expressing both sides of the equation as powers of 5. We know that:- 125 can be rewritten as \(5^3\), because \(125 = 5 \times 5 \times 5\).- 25 can be rewritten as \(5^2\), because \(25 = 5 \times 5\).Thus, the equation \(125^{x-2} = 25\) becomes \((5^3)^{x-2} = 5^2\).
2Step 2: Apply the Power of a Power Property
Next, we apply the power of a power property \((a^m)^n = a^{m\cdot n}\) to the left side of the equation:\[(5^3)^{x-2} = 5^{3(x-2)}.\]
3Step 3: Set the Exponents Equal to Each Other
Since the bases are now the same on both sides (both are 5), we can set the exponents equal to each other:\[3(x-2) = 2.\]
4Step 4: Solve for x
We solve this equation for \(x\):- First, distribute the 3 on the left side: \(3x - 6 = 2.\)- Add 6 to both sides: \(3x = 8.\)- Divide both sides by 3: \(x = \frac{8}{3}.\)
Key Concepts
Powers of 5Power of a Power PropertySolving Equations with Exponents
Powers of 5
Exponents simplify multiplication by indicating how many times a number, called the base, is multiplied by itself. For example, in the expression
By recognizing that 125 is \(5^3\) and 25 is \(5^2\), it becomes easier to compare and manipulate expressions with these powers. This skill is fundamental in solving equations where terms need to be expressed with the same base.
- \(5^3\), we are multiplying 5 by itself 3 times: \(5 \times 5 \times 5 = 125\).
- Similarly, \(5^2\) means 5 is multiplied by itself 2 times: \(5 \times 5 = 25\).
By recognizing that 125 is \(5^3\) and 25 is \(5^2\), it becomes easier to compare and manipulate expressions with these powers. This skill is fundamental in solving equations where terms need to be expressed with the same base.
Power of a Power Property
The "Power of a Power" property in exponents is a handy rule that allows us to simplify expressions where an exponent is raised to another exponent. The rule states that
Let's consider the expression \((5^3)^{x-2}\). Using the power of a power property, we simplify this to \(5^{3(x-2)}\).
This step transforms the equation into a familiar form where only the exponents need to be considered, making it easier to isolate the variable and solve the equation.
- \((a^m)^n = a^{m \cdot n}\).
Let's consider the expression \((5^3)^{x-2}\). Using the power of a power property, we simplify this to \(5^{3(x-2)}\).
This step transforms the equation into a familiar form where only the exponents need to be considered, making it easier to isolate the variable and solve the equation.
Solving Equations with Exponents
Equations with exponents often require isolating the variable by using properties of exponents. Start by ensuring the bases on both sides of the equation are the same, as this allows you to compare the exponents directly.
In our example, we have
In our example, we have
- \(5^{3(x-2)} = 5^2\).
- \(3(x-2) = 2\).
- Distributing and simplifying: \(3x - 6 = 2\).
- Adding 6 to both sides: \(3x = 8\).
- Finally, dividing by 3: \(x = \frac{8}{3}\).
Other exercises in this chapter
Problem 32
Solve each equation. Give an exact solution and a four-decimal-place approximation. $$ \log x=2.1 $$
View solution Problem 32
Find the inverse of each one-to-one function. $$ f(x)=\frac{4 x-3}{2} $$
View solution Problem 32
Find \(f(x)\) and \(g(x)\) so that the given function \(h(x)=(f \circ g)(x)\). $$ h(x)=|x-1| $$
View solution Problem 32
Write each as a single logarithm. Assume that variables represent positive numbers. $$ \log _{8} 5+\log _{8} 15-\log _{8} 20 $$
View solution