Problem 32
Question
Sketch the quadric surface. \(4 x^{2}+2 y^{2}+z^{2}=4\)
Step-by-Step Solution
Verified Answer
The surface is an ellipsoid centered at the origin.
1Step 1: Rewrite the Equation in Standard Form
Start by dividing all terms of the equation \(4x^2 + 2y^2 + z^2 = 4\) by 4 to simplify it. This gives: \(\frac{x^2}{1} + \frac{y^2}{2} + \frac{z^2}{4} = 1\). This is the standard form of a quadric surface.
2Step 2: Identify the Type of Quadric Surface
The equation \(\frac{x^2}{1} + \frac{y^2}{2} + \frac{z^2}{4} = 1\) matches the standard form of an ellipsoid, which is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1\). Thus, the surface is an ellipsoid with semi-axis lengths \(a = 1\), \(b = \sqrt{2}\), and \(c = 2\).
3Step 3: Sketch the Ellipsoid
1. Draw the coordinate axes: x, y, and z.2. Plot points at the ends of each semi-axis: (1, 0, 0), (-1, 0, 0) for x-axis, (0, \(\sqrt{2}\), 0), (0, -\(\sqrt{2}\), 0) for y-axis, and (0, 0, 2), (0, 0, -2) for z-axis.3. Connect these points with an oval shape representing the ellipsoid.The sketch should be symmetrical about each of the axes, reflecting how lengths are scaled by the values of a, b, and c.
Key Concepts
EllipsoidStandard FormSemi-Axis Lengths
Ellipsoid
An ellipsoid is a type of quadric surface that is a three-dimensional shape. Imagine a roundish stretched-out sphere. Much like how a circle turns into an ellipse when drawn flat, a sphere becomes an ellipsoid when extended in different directions. The defining characteristic of an ellipsoid is its symmetry about three perpendicular axes. This symmetry is deeply rooted in the equation used to describe it.
For an ellipsoid, the general equation in standard form is given by:
For an ellipsoid, the general equation in standard form is given by:
- \( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \)
Standard Form
Mathematical equations often have a 'standard form', which simplifies analysis and identification. For an ellipsoid, the standard form helps in easily spotting the type of surface and determining its key properties. In the given problem, the starting equation is \(4x^2 + 2y^2 + z^2 = 4\). By dividing all terms by the number on the right-hand side, 4, it transforms into:
- \( \frac{x^2}{1} + \frac{y^2}{2} + \frac{z^2}{4} = 1 \)
Semi-Axis Lengths
The semi-axis lengths \(a\), \(b\), and \(c\) are fundamental to defining the shape of an ellipsoid. They represent how far the ellipsoid stretches along each axis from the center to the surface. These lengths tell us the dimensions and proportions of the shape.
- For the x-axis, we have \(a = \sqrt{1} \), which simplifies to 1.
- On the y-axis, \(b = \sqrt{2} \) shows an intermediate length.
- The z-axis is the longest with \(c = \sqrt{4} = 2 \).
Other exercises in this chapter
Problem 32
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