Problem 32
Question
Perform the indicated operations and simplify. \(2+\frac{1}{a+2}-\frac{2 a}{a-2}\)
Step-by-Step Solution
Verified Answer
The simplified expression for the given problem is: \(-\frac{2a^2 + 3a + 2}{(a+2)(a-2)}\)
1Step 1: Identify the common denominator
Identify the common denominator for the fractions. In this case, the denominators are \((a+2)\) and \((a-2)\). The common denominator will be the product of these two, which is \((a+2)(a-2)\).
2Step 2: Rewrite the fractions with the common denominator
Now let's rewrite the fractions with the common denominator, \((a+2)(a-2)\):
\[\frac{1}{a+2}=\frac{1(a-2)}{(a+2)(a-2)}=\frac{a-2}{(a+2)(a-2)}\]
\[\frac{2a}{a-2}=\frac{2a(a+2)}{(a-2)(a+2)}=\frac{2a(a+2)}{(a+2)(a-2)}\]
3Step 3: Perform addition and subtraction
Now we perform the addition and subtraction operations of the rewritten fractions:
\[2+\frac{a-2}{(a+2)(a-2)}-\frac{2a(a+2)}{(a+2)(a-2)}\]
Note that we can simply subtract the numerators, as the denominators are the same:
\[\frac{(a-2)-2a(a+2)}{(a+2)(a-2)}\]
4Step 4: Simplify the numerator
Now, let's simplify numerator of the fraction:
\[(a-2)-2a(a+2)= a - 2 - 2a^2 - 4a = -2a^2 - 3a - 2\]
5Step 5: Write the simplified expression
Combine the simplified numerator with the denominator to get the final simplified expression:
\[-\frac{2a^2+ 3a + 2}{(a+2)(a-2)}\]
As we simplified the expression, this is the final answer.
Key Concepts
Common DenominatorFraction OperationsExpression Simplification
Common Denominator
When working with fractions, especially in algebraic expressions, finding a common denominator is crucial. A common denominator is a shared multiple of the denominators of two or more fractions. This step is needed to perform addition or subtraction among these fractions.
In the given problem, the denominators are \(a+2\) and \(a-2\). The simplest common denominator is their product, \( (a+2)(a-2) \). Here’s why:
In the given problem, the denominators are \(a+2\) and \(a-2\). The simplest common denominator is their product, \( (a+2)(a-2) \). Here’s why:
- Multiplying \(a+2\) by \(a-2\) gives us a single expression that accommodates both fractions.
- This allows for seamless integration when adding or subtracting.
Fraction Operations
Operating on fractions (addition, subtraction, etc.) requires particular attention to maintaining a common denominator. This allows changes made to the numerators to be harmonized without altering the overall meaning of the fractions.
Here's how it works with our example:
Here's how it works with our example:
- Once the common denominator \( (a+2)(a-2) \) is in place, rewrite each fraction accordingly.
- This involves adjusting the numerators so that they align with the new denominator.
- Multiplying the numerator of each fraction by whatever quantity the denominator was multiplied by.
- Ensuring every operation obeys the fundamental rules of algebra, such as distribution.
Expression Simplification
Simplifying an expression is often the goal when handling algebraic problems. It involves reducing an expression to its simplest form while maintaining equivalency. In our continued example, after aligning fractions with a common denominator, we simplified the numerator:
- Using the formula from subtraction, we saw \( (a-2) - 2a(a+2) \) needed simplifying.
- Distribute any multiplication through to clear parentheses: \( -2a^2 - 4a \).
- Combine like terms to collapse the expression further.
Other exercises in this chapter
Problem 31
State the real number property that iustifies the statement $$ \frac{(x+1)(x-3)}{(2 x+1)(x-3)}=\frac{x+1}{2 x+1} $$
View solution Problem 31
Perform the indicated operations and simplify. $$ (2 x-3 y)(3 x+2 y) $$
View solution Problem 32
Evaluate the expression. $$ \left|\frac{0.2-1.4}{1.6-2.4}\right| $$
View solution Problem 32
Solve the equation by using the quadratic formula. $$ 6 p-6=p^{2} $$
View solution