Problem 32
Question
Parametrization of a surface of revolution Suppose that the parametrized curve \(C :(f(u), g(u))\) is revolved about the \(x\) -axis, where \(g(u)>0\) for \(a \leq u \leq b .\) a. Show that $$ \mathbf{r}(u, v)=f(u) \mathbf{i}+(g(u) \cos v) \mathbf{j}+(g(u) \sin v) \mathbf{k} $$ is a parametrization of the resulting surface of revolution, where \(0 \leq v \leq 2 \pi\) is the angle from the \(x y\) -plane to the point \(\mathbf{r}(u, v)\) on the surface. (See the accompanying figure.) Notice that \(f(u)\) measures distance along the axis of revolution and \(g(u)\) measures distance from the axis of revolution. b. Find a parametrization for the surface obtained by revolving the curve \(x=y^{2}, y \geq 0,\) about the \(x\) -axis.
Step-by-Step Solution
VerifiedKey Concepts
Surface of Revolution
For example, consider revolving a semicircle about the x-axis. You would generate a sphere. In our case, the curve described by \(f(u), g(u)\) is revolved around the x-axis, creating a 3D surface. The function \(f(u)\) is responsible for the distance along the axis, while \(g(u)\) determines how far each point on the curve is from the axis. This behavior is crucial because it dictates the shape formed during revolution, impacting both surface area and volume calculations. Understanding surface of revolution helps in visualizing complex shapes formed in engineering and various applied fields.
Parametric Equations
- For a single curve, a parametric form \(\text{like } C: (f(u), g(u))\)\