Problem 32
Question
Locate the absolute extrema of the function (if any exist) over each interval. \(f(x)=\sqrt{4-x^{2}}\) (a) [-2,2] (b) [-2,0) (c) (-2,2) (d) [1,2)
Step-by-Step Solution
Verified Answer
The absolute extrema for the given intervals are: (a) [-2, 2] maximum at f(0) = 2, minimum at f(-2) = f(2) = 0; (b) [-2, 0) maximum at f(0) = 2, minimum at f(-2) = 0; (c) (-2, 2) the maximum at f(0) = 2, no minimum; and (d) [1, 2) maximum at f(1) = \(\sqrt{3}\), minimum at f(2) = 0.
1Step 1: Finding the first derivative
To find where the absolute extrema occurs, it's necessary to find where the derivative equals 0 or is undefined. The derivative of \(f(x)=\sqrt{4-x^{2}}\), using the chain rule, is \(f'(x) = -x/\sqrt{4-x^{2}}\).
2Step 2: Finding the critical points
Set the derivative to 0 and solve for x, it's impossible because the fraction is 0 when the numerator is 0, but if \(x = 0\), the denominator is non-zero. Therefore, there's no real solutions, which means there's no critical points except the end points.
3Step 3: Substituting end points and critical points into original function
Substitute the endpoints of the interval and the critical points (if exist) into the original function. For the interval [-2,2], the endpoints are x = -2, 2. Therefore, the maximum and minimum values are the maximum and minimum of f(-2), f(2), which is also the maximum and minimum of -\(\sqrt{4}\), \(\sqrt{4}\). Repeat this step for each of the intervals [(a), (b), (c), and (d)].
4Step 4: Identifying the absolute extrema
The absolute extrema are the maximum and minimum values calculated in Step 3. For each interval, identify the smallest and largest values.
Key Concepts
Absolute ExtremaCritical PointsDerivativeIntervals
Absolute Extrema
When we talk about absolute extrema, we are referring to the highest or lowest points the function achieves on a given interval. These points are found by plugging in specific x-values into the function. Absolute extrema are crucial because they help us understand the behavior of a function over a particular range.
- Absolute Maximum: Largest y-value on the interval
- Absolute Minimum: Smallest y-value on the interval
Critical Points
Critical points are the x-values where a function's derivative equals zero or is undefined. These are crucial in determining a function's behavior because they are potential points where the function's direction changes, which may correspond to a local maximum or minimum.
- Set the derivative equal to zero and solve for x
- If the derivative does not exist at a point, that point is also a critical point
Derivative
The derivative of a function gives us the slope or rate of change at any given point. In simple terms, it tells us how the function is behaving: increasing, decreasing, or staying flat. Derivatives are indispensable in calculus, especially when it comes to finding extrema points.
- Use derivative to check for increasing/decreasing functions
- Find points where derivative is zero for potential extrema
Intervals
In calculus, an interval refers to a specific range of x-values over which we examine a function. Calculating extrema over different intervals can yield different results, emphasizing the importance of context when analyzing functions. An interval can be:
- Closed: Includes its endpoints, noted by brackets \([a, b]\)
- Open: Does not include endpoints, noted by parentheses \((a, b)\)
- Half-open: Includes only one endpoint, e.g., \([a, b)\) or \((a, b]\)
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