Problem 32
Question
Is \(\langle S, \cup, \cap,, \emptyset, U)\) a boolean algebra for each subset \(S\) of \(P(U),\) where \(U=[a, b, c] ?\) $$ \\{\emptyset,|a|,|b|,\\{a, b |, U\\} $$
Step-by-Step Solution
Verified Answer
The given structure 𝑆 is not a Boolean algebra because it does not satisfy the Complement Law for all subsets of P(U). All other axioms are satisfied.
1Step 1: Determine the Power set of U (P(U))
Calculate the possible subsets of the given set U to form its power set.
P(U) = {∅, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c}}
2Step 2: Check the Commutative Law
Verify the Commutative law is true for the subsets of P(U).
A ∪ B = B ∪ A and A ∩ B = B ∩ A
The Commutative law is satisfied for all subsets of P(U).
3Step 3: Check the Associative Law
Verify the Associative law is true for the subsets of P(U).
(A ∪ B) ∪ C = A ∪ (B ∪ C) and (A ∩ B) ∩ C = A ∩ (B ∩ C)
The Associative law is satisfied for all subsets of P(U).
4Step 4: Check the Identity Law
Verify the Identity law is true for the subsets of P(U).
A ∪ ∅ = A and A ∩ U = A
The Identity law is satisfied for all subsets of P(U).
5Step 5: Check the Distributive Law
Verify the Distributive law is true for the subsets of P(U).
A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C) and A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
The Distributive law is satisfied for all subsets of P(U).
6Step 6: Check the Complement Law
Verify the Complement law is true for the subsets of P(U).
A ∪ A' = U and A ∩ A' = ∅
The Complement law is not satisfied for all subsets of P(U).
Since the Complement Law is not satisfied for all subsets of P(U), the given structure 𝑆 is not a Boolean algebra.
Key Concepts
Power SetCommutative LawAssociative LawIdentity Law
Power Set
The concept of a power set is foundational in set theory. When we talk about the power set of a given set, we are referring to the set that includes all possible subsets of the original set. It also includes the empty set and the set itself. For instance, if we have a set \(U = \{a, b, c\}\), its power set, denoted as \(P(U)\), would be:
- \(\emptyset\) (Empty Set)
- \(\{a\}\), \(\{b\}\), \(\{c\}\) (Single element subsets)
- \(\{a, b\}\), \(\{a, c\}\), \(\{b, c\}\) (Two elements subsets)
- \(\{a, b, c\}\) (The set itself)
Commutative Law
The commutative law is a principle found in mathematics that states the order in which you apply a binary operation does not change the result. In the context of set theory, this law applies to the operations of union (\(\cup\)) and intersection (\(\cap\)). For example:
- Union: \(A \cup B = B \cup A\), meaning adding set \(A\) to \(B\) is the same as adding \(B\) to \(A\).
- Intersection: \(A \cap B = B \cap A\), which means the common elements of \(A\) and \(B\) remain the same regardless of the order.
Associative Law
The associative law, like the commutative law, is another important property in mathematics applied to operations such as union and intersection. This law implies that when we group three or more elements and perform an operation, the outcome remains unaffected by the grouping of those elements. For example:
- Union: \((A \cup B) \cup C = A \cup (B \cup C)\)
- Intersection: \((A \cap B) \cap C = A \cap (B \cap C)\)
Identity Law
Identity laws help define simple truths within mathematics, particularly in set operations. For sets, they explain how certain operations will leave a set unchanged when combined with specific elements. For example:
- Union: \(A \cup \emptyset = A\), meaning adding the empty set to any set \(A\) leaves \(A\) unchanged.
- Intersection: \(A \cap U = A\), where \(U\) is the universal set containing all possible elements within the context, intersecting any set \(A\) with \(U\) yields \(A\) itself.
Other exercises in this chapter
Problem 31
Is \(\left\langle S, \cup, \cap,^{\prime}, \emptyset, U\right\rangle\) a boolean algebra for each subset \(S\) of \(P(U),\) where \(U=\\{a, b, c\\} ?\) $$\\{\em
View solution Problem 32
Using a Karnaugh map, simplify each boolean expression. $$x y z+x y z^{\prime}+x^{\prime} y^{\prime} z^{\prime}+x^{\prime} y^{\prime} z$$
View solution Problem 32
Find the DNFs of the boolean functions $$\begin{array}{|ccc||c|} \hline x & y & z & f(x, y, z) \\ \hline 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 1 & 0 & 0 \\ 0 &
View solution Problem 32
Is \(\left\langle S, \cup, \cap,^{\prime}, \emptyset, U\right\rangle\) a boolean algebra for each subset \(S\) of \(P(U),\) where \(U=\\{a, b, c\\} ?\) $$\\{\em
View solution