Problem 32
Question
In Problems \(29-48\), find the limits. $$ \lim _{x \rightarrow-\pi / 2} \frac{1+\tan ^{2} x}{\sec ^{2} x} $$
Step-by-Step Solution
Verified Answer
The limit is 1.
1Step 1: Identify the Trigonometric Identity
We start by recognizing the trigonometric identity that relates tangent and secant. Recall that the identity is \(1 + \tan^2 x = \sec^2 x\). We can use this identity to simplify the given limit.
2Step 2: Simplify the Expression with the Identity
Using the identity from Step 1, substitute \( \sec^2 x \) for \( 1 + \tan^2 x \) in the limit expression. This gives us: \[\lim_{x \to -\pi/2} \frac{\sec^2 x}{\sec^2 x}\] This simplifies to: \[\lim_{x \to -\pi/2} 1\]
3Step 3: Evaluate the Simplified Limit
The expression \( \lim_{x \to -\pi/2} 1 \) is straightforward because it represents a constant function. The limit of a constant is simply the constant itself.
Key Concepts
Trigonometric IdentitiesLimit EvaluationSimplifying Expressions
Trigonometric Identities
In calculus, trigonometric identities play a crucial role, especially when working with limits. These identities are equations involving trigonometric functions that are true for every value of the involved variables. A key identity used in many limit problems is the Pythagorean identity:
For example, in our initial problem, understanding that the expression \(1 + \tan^2 x\) is equal to \(\sec^2 x\) allows us to easily substitute and simplify the expression. Hence, good knowledge of these identities is a powerful tool for anyone learning calculus.
- \(1 + \tan^2 x = \sec^2 x\)
For example, in our initial problem, understanding that the expression \(1 + \tan^2 x\) is equal to \(\sec^2 x\) allows us to easily substitute and simplify the expression. Hence, good knowledge of these identities is a powerful tool for anyone learning calculus.
Limit Evaluation
Limit evaluation is a fundamental concept in calculus, and it involves finding the value that a function approaches as the input (or variable) approaches some value. When evaluating limits, especially those involving trigonometric functions, substituting known identities often simplifies the task.
In the given exercise, we are evaluating the limit as \(x\) approaches \(-\pi/2\). Through simplification, it becomes a constant function.
In the given exercise, we are evaluating the limit as \(x\) approaches \(-\pi/2\). Through simplification, it becomes a constant function.
- Direct substitution is the process of plugging the value into the simplified function.
- Since our expression \(\frac{\sec^2 x}{\sec^2 x}\) simplifies to \(1\), the limit is evaluated as \(1\).
Simplifying Expressions
Simplifying expressions is all about making a complex expression easier to work with. This can involve combining like terms, factoring, or using identities. A simplified expression not only looks tidier, but it’s also often much easier to work with in further calculus operations.
The importance of simplifying cannot be overstated. In the original problem, simplifying \(\frac{1+\tan^2 x}{\sec^2 x}\) to \(\frac{\sec^2 x}{\sec^2 x}\) shows an immediate simplification to \(1\).
The importance of simplifying cannot be overstated. In the original problem, simplifying \(\frac{1+\tan^2 x}{\sec^2 x}\) to \(\frac{\sec^2 x}{\sec^2 x}\) shows an immediate simplification to \(1\).
- Such simplification instantly clarifies that no further calculations are needed to find the limit.
- This reduction from a seemingly complex fraction to a constant illustrates the power of recognizing and applying identities.
Other exercises in this chapter
Problem 31
In Problems \(29-48\), find the limits. $$ \lim _{x \rightarrow \pi / 2} \frac{\cos ^{2} x}{1-\sin ^{2} x} $$
View solution Problem 32
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 0} \frac{\sqrt{2-x}-\sqrt{2}}{2 x} $$
View solution Problem 33
In Problems \(29-48\), find the limits. $$ \lim _{x \rightarrow-1} \sqrt{4+5 x^{4}} $$
View solution Problem 34
Use a table and a graph to find out what happens to $$ f(x)=\frac{2 x}{x-1} $$ as \(x \rightarrow \infty\). What happens as \(x \rightarrow-\infty\) ? What happ
View solution