Problem 32
Question
In Exercises \(31-34,\) find the line's \(x\) - and \(y\) -intercepts and use this information to graph the line. $$ x+2 y=-4 $$
Step-by-Step Solution
Verified Answer
The x-intercept is (-4, 0) and the y-intercept is (0, -2).
1Step 1: Identify Equation Form
We start with the linear equation given: \( x + 2y = -4 \). This is in standard form \( Ax + By = C \), where \( A = 1 \), \( B = 2 \), and \( C = -4 \).
2Step 2: Find the x-intercept
To find the x-intercept, set \( y = 0 \) in the equation \( x + 2y = -4 \). This results in \( x + 2(0) = -4 \), simplifying to \( x = -4 \). Thus, the x-intercept is \( (-4, 0) \).
3Step 3: Find the y-intercept
To find the y-intercept, set \( x = 0 \) in the equation \( x + 2y = -4 \). This results in \( 0 + 2y = -4 \), or \( 2y = -4 \). Solving for \( y \), we divide both sides by 2, yielding \( y = -2 \). Hence, the y-intercept is \( (0, -2) \).
4Step 4: Plot the Intercepts
Plot the intercepts found: the x-intercept \( (-4, 0) \) and the y-intercept \( (0, -2) \) on the Cartesian coordinate plane.
5Step 5: Draw the Line
Draw a straight line connecting the two plotted intercept points. This is the graph of the line represented by the equation \( x + 2y = -4 \).
Key Concepts
Understanding X-InterceptsUnderstanding Y-InterceptsGraphing Lines Using Intercepts
Understanding X-Intercepts
An x-intercept is where a line crosses the x-axis. At this point, the value of y is always zero. You can find the x-intercept of an equation by substituting zero for y and solving for x. This gives you the precise point where the line meets the x-axis.
In our example equation, \( x + 2y = -4 \), setting \( y = 0 \) leads to \( x = -4 \). Thus, the x-intercept is \((-4, 0)\).
Understanding x-intercepts helps in graphing, because it gives one of the key locations through which the line passes. This is crucial for an accurate graph.
In our example equation, \( x + 2y = -4 \), setting \( y = 0 \) leads to \( x = -4 \). Thus, the x-intercept is \((-4, 0)\).
Understanding x-intercepts helps in graphing, because it gives one of the key locations through which the line passes. This is crucial for an accurate graph.
- Set \( y = 0 \) in the equation to find the x-intercept.
- Solve the resulting equation for x to get the intercept point.
- Interpret the intercept as a coordinate \( (x, 0) \).
Understanding Y-Intercepts
A y-intercept is the point where a line crosses the y-axis. At this point, the value of x is always zero. To find the y-intercept, you need to set x to zero in the equation and solve for y. This tells you exactly where the line meets the y-axis.
Using the same example, \( x + 2y = -4 \), by setting \( x = 0 \), we find that \( y = -2 \). This makes the y-intercept \((0, -2)\).
Knowing the y-intercept is essential for graphing a line because it gives another vital point to accurately place the line on the graph.
Using the same example, \( x + 2y = -4 \), by setting \( x = 0 \), we find that \( y = -2 \). This makes the y-intercept \((0, -2)\).
Knowing the y-intercept is essential for graphing a line because it gives another vital point to accurately place the line on the graph.
- Set \( x = 0 \) in the equation to determine the y-intercept.
- Solve for y to find the corresponding intercept point.
- Understand this intercept as a coordinate \( (0, y) \).
Graphing Lines Using Intercepts
Graphing a line using its x- and y-intercepts is straightforward and efficient. To graph a line, these intercepts are plotted on a coordinate plane to provide clear guidance on the line's path.
For the equation \( x + 2y = -4 \), you've already found two crucial points: the x-intercept \((-4, 0)\) and the y-intercept \((0, -2)\). These points help form the backbone of the line.
To graph:
For the equation \( x + 2y = -4 \), you've already found two crucial points: the x-intercept \((-4, 0)\) and the y-intercept \((0, -2)\). These points help form the backbone of the line.
To graph:
- First, plot the x-intercept \((-4, 0)\) on the graph.
- Next, plot the y-intercept \((0, -2)\).
- Finally, draw a straight line connecting these two points.
Other exercises in this chapter
Problem 32
Use the addition formulas to derive the identities in Exercises \(31-36\) $$ \cos \left(x+\frac{\pi}{2}\right)=-\sin x $$
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In Exercises 31 and \(32,\) assess whether the given data sets reasonably support the stated proportionality assumption. Graph an appropriate scatterplot for yo
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Solve the inequalities in Exercises \(19-34,\) expressing the solution sets as intervals or unions of intervals. Also, show each solution set on the real line.
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For what values of \(x\) is a. \(\lfloor x\rfloor= 0 ? \quad\) b. \(\lceil x\rceil= 0 ?\)
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