Problem 32
Question
In Exercises 29-34, find the standard form of the equation of the hyperbola with the given characteristics and center at the origin. Vertices: \((0, \pm3); \quad\) asymptotes: \(y=\pm3x\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the hyperbola is \(\frac{y^2}{9} - \frac{x^2}{9} = 1\).
1Step 1: Identify and define key variables
Here, 'a' is the distance from the center to a vertex, in this case is 3 (from (0, ±3)). 'b' is going to be the slope of the asymptote, which is also 3 (from y=±3x).
2Step 2: Write the general equation
The general equation of a hyperbola that opens upwards and downwards is \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\).
3Step 3: Substitute 'a' and 'b' into the equation
Now, substitute a and b values (which are both 3 in this case) into the general equation. So the equation becomes: \(\frac{y^2}{3^2} - \frac{x^2}{3^2} = 1\). Simplify it to get: \(\frac{y^2}{9} - \frac{x^2}{9} = 1\).
Key Concepts
Standard FormVerticesAsymptotesEquationCenter at the Origin
Standard Form
The standard form of the hyperbola's equation helps define its shape. For a hyperbola centered at the origin with vertical transverse axis, the standard form is \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\). This structure allows us to identify important elements like the distances to the vertices and the slopes of the asymptotes.
When you see a hyperbola's equation, you can instantly recognize whether it opens up-down or side-to-side, depending on which term, \( y^2 \) or \( x^2 \), comes first. For vertical opening, \( y^2 \) comes first as shown, while for horizontal opening, \( x^2 \) comes first in the subtraction. Understanding the standard form is crucial for graphing a hyperbola accurately.
When you see a hyperbola's equation, you can instantly recognize whether it opens up-down or side-to-side, depending on which term, \( y^2 \) or \( x^2 \), comes first. For vertical opening, \( y^2 \) comes first as shown, while for horizontal opening, \( x^2 \) comes first in the subtraction. Understanding the standard form is crucial for graphing a hyperbola accurately.
Vertices
Vertices are two specific points on the hyperbola that illustrate its width along the transverse axis. For our hyperbola, the vertices are at \((0, \pm3)\). Here, \(a\), the distance from the center to a vertex, is a central component.
In the format \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\):
In the format \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\):
- \(a\) is calculated as 3.
- Vertices will always be reached directly along the y-axis at \( (0, 3) \) and \( (0, -3) \) for this equation.
Asymptotes
Asymptotes are imaginary lines that a hyperbola approaches but never touches. They define the hyperbola's slant and its opening direction. In our example, the asymptotes are \(y = \pm3x\).
These lines indicate the slope \( \frac{a}{b} = \pm3 \), where:
These lines indicate the slope \( \frac{a}{b} = \pm3 \), where:
- \( a = 3 \)
- \( b = 3 \)
Equation
The core of the exercise is defining the hyperbola's equation. Plugging values into the equation of a hyperbola gives us \(\frac{y^2}{9} - \frac{x^2}{9} = 1\). This result is achieved by substituting \( a = 3 \) and \( b = 3 \) into the formula \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\).
Let's break down the calculation:
Let's break down the calculation:
- Since \(a = 3\), \(a^2 = 9\).
- And because \(b = 3\), \(b^2 = 9\).
Center at the Origin
Placing the hyperbola at the origin makes the math cleaner and easier to handle. When the center is \((0,0)\), it simplifies the structure of the equation, avoiding additional terms.
The center position allows vertices, centers, and asymptotes to align with straightforward math:
The center position allows vertices, centers, and asymptotes to align with straightforward math:
- Vertices derive straightforwardly without added terms, lying directly on the xy-axes.
- The equation's symmetry is simplified, making transformations manageable.
Other exercises in this chapter
Problem 32
In Exercises 29-32, eliminate the parameter and obtain the standard form of the rectangular equation. Hyperbola: \(\quad x=h+a\ \sec\ \theta, \quad y=k + b\ \ta
View solution Problem 32
In Exercises 27-36, use a graphing utility to graph the conic. Determine the angle \(\theta\) through which the axes are rotated.Explain how you used the graphi
View solution Problem 32
In Exercises 29-52, identify the conic as a circle or an ellipse. Then find the center, radius, vertices, foci, and eccentricity of the conic (if applicable), a
View solution Problem 32
In Exercises 19-32, find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Horizontal axis and passes
View solution