Problem 32
Question
If \(N=6^{\log _{10} 40} .5^{\log _{10} 36}\), then find the value of \(N+10\).
Step-by-Step Solution
Verified Answer
The value of \(N+10\) is 1450.
1Step 1: Simplify the expression for N
Apply \(b^{log_bx}=x\) i.e the base \(b\) of the logarithm and the base \(b\) of the power are the same. So, it simplifies to \(N=40*36=1440\).
2Step 2: Calculate the value of N+10
After simplifying the value of \(N\), add 10 to it i.e \(N+10=1440+10=1450\).
Key Concepts
Exponential FunctionsLogarithmic IdentitiesSimplification Techniques
Exponential Functions
Exponential functions are mathematical expressions wherein a constant base is raised to a variable exponent. These functions are central to multiple areas in mathematics due to their properties of rapid growth or decay.
Exponential expressions generally take the form of \(a^x\), where \(a\) is a constant known as the base, and \(x\) is the exponent or power.
Such functions are widely applied in growth and decay processes like population growth, radioactive decay, and compound interest.
Exponential expressions generally take the form of \(a^x\), where \(a\) is a constant known as the base, and \(x\) is the exponent or power.
Such functions are widely applied in growth and decay processes like population growth, radioactive decay, and compound interest.
- The function \(b^{\log_b x} = x\) is a useful identity that simplifies the expression when the base of the exponent matches the base of the logarithm.
- An exponential function can often be rearranged or simplified using logarithmic identities.
Logarithmic Identities
Logarithmic identities are rules that simplify expressions involving logarithms, making complex calculations more feasible. They are based on the properties of logarithms, which serve as the inverse operations of exponential functions.
Some key identities include:
Some key identities include:
- \(\log_b(xy) = \log_b x + \log_b y\)
- \(\log_b\left(\frac{x}{y}\right) = \log_b x - \log_b y\)
- \(\log_b(x^n) = n \log_b x\)
- \(b^{\log_b x} = x\), which was particularly used in the original problem to simplify the expression, as the base \(b\) and the log base match, allowing the exponent's logarithmic base to cancel out.
Simplification Techniques
Simplification techniques in the context of logarithms and exponential functions often involve using identities to reduce complex expressions into more manageable forms.
In the given problem, simplification was achieved using the identity \(b^{\log_b x} = x\), effectively reducing it to basic arithmetic.
In the given problem, simplification was achieved using the identity \(b^{\log_b x} = x\), effectively reducing it to basic arithmetic.
- First, recognize where logarithmic identities can apply, as with \(\log_b x\) and the corresponding base \(x\).
- Another simplification trick involves breaking down expressions to see if identities apply, as seen with different bases in exponential forms.
- Simplifying expressions step-by-step helps avoid confusion and errors in larger problems, making it easier to evaluate final results accurately.
Other exercises in this chapter
Problem 28
Find \(x\), if \(\log _{2} x+\log _{4} x+\log _{8} x+\log _{16} x=\frac{25}{4}\)
View solution Problem 30
If \(x=\log _{a} b c, y=\log _{b} c a\) and \(z=\log _{c} a b\), then find the value of \(\frac{1}{1+x}+\frac{1}{1+y}+\frac{1}{1+z}\)
View solution Problem 34
If \(x=2^{\log _{10} 3}\) and \(y=3^{\log _{i 0} 2}\), then find a relation between \(x\) and \(y\).
View solution Problem 35
$$ \begin{aligned} &\text { Find the value of }\\\ &2^{\log _{40} 3-\log _{10} 5} \times 3^{\log _{40} 5-\log _{10} 2} \times 5^{\log _{10} 2-\log _{10} 3} \end
View solution