Problem 32
Question
For the following problems, perform the multiplications and divisions. $$ \frac{x+10}{x-4} \cdot \frac{x-4}{x-1} $$
Step-by-Step Solution
Verified Answer
Question: Simplify the following expression:
$
\frac{x+10}{x-4} \cdot \frac{x-4}{x-1}
$
Answer: $\frac{x+10}{x-1}$
1Step 1: Identify Common Factors
First, we can notice that the numerator of the second fraction and the denominator of the first fraction have a common factor, \((x-4)\). This will be helpful when simplifying the expression.
2Step 2: Cancel Out Common Factors
Now, we can cancel out the common factor \((x-4)\) in the numerator and denominator:
$$
\frac{x+10}{x-4} \cdot \frac{x-4}{x-1} = \frac{x+10}{\cancel{x-4}} \cdot \frac{\cancel{x-4}}{x-1}
$$
3Step 3: Perform the Multiplication
After canceling out the common factors, we can perform the multiplication and obtain the final simplified expression:
$$
\frac{x+10}{1} \cdot \frac{1}{x-1} = \frac{x+10}{x-1}
$$
So the result is:
$$
\frac{x+10}{x-1}
$$
Key Concepts
Simplifying ExpressionsCommon FactorsMultiplication and Division of Fractions
Simplifying Expressions
Simplifying expressions is a fundamental skill in algebra that makes handling equations much more manageable. When you simplify an expression, you aim to write it in the most reduced form. Doing this involves combining like terms and eliminating any unnecessary parts. The process helps in understanding complex expressions by making them simpler and more straightforward.
In the context of rational expressions, simplification means cancelling out any common factors that appear in both the numerator and the denominator. For example, in the expression \(\frac{x+10}{x-4} \cdot \frac{x-4}{x-1}\), the \((x-4)\) appears in both the numerator of the second fraction and the denominator of the first. This tells us it can be cancelled out from the expression, making it easier to simplify further.
In the context of rational expressions, simplification means cancelling out any common factors that appear in both the numerator and the denominator. For example, in the expression \(\frac{x+10}{x-4} \cdot \frac{x-4}{x-1}\), the \((x-4)\) appears in both the numerator of the second fraction and the denominator of the first. This tells us it can be cancelled out from the expression, making it easier to simplify further.
Common Factors
Common factors are elements or numbers shared by the two or more terms in an expression. Finding these common factors is crucial for simplifying expressions effectively. In each rational expression, the goal is to identify these elements so that they can be cancelled.
In the example problem \(\frac{x+10}{x-4} \cdot \frac{x-4}{x-1}\), the expression \((x-4)\) is a common factor present in both the numerator of the second fraction and the denominator of the first. By recognizing this, we notice that \((x-4)\) can be removed from these terms. This is because any non-zero number divided by itself equals 1, hence \((x-4)/(x-4) = 1\). This step significantly reduces the complexity of the expression and leads to the simplified result \(\frac{x+10}{x-1}\).
In the example problem \(\frac{x+10}{x-4} \cdot \frac{x-4}{x-1}\), the expression \((x-4)\) is a common factor present in both the numerator of the second fraction and the denominator of the first. By recognizing this, we notice that \((x-4)\) can be removed from these terms. This is because any non-zero number divided by itself equals 1, hence \((x-4)/(x-4) = 1\). This step significantly reduces the complexity of the expression and leads to the simplified result \(\frac{x+10}{x-1}\).
Multiplication and Division of Fractions
The multiplication and division of fractions involves straightforward steps. For multiplication, you multiply numerators with numerators and denominators with denominators. However, a smart initial step is simplifying first. This reduces the effort and calculation involved.
In division, we often talk of multiplying by the reciprocal of the divisor. But in some instances, like our problem, it's easier to spot and eliminate common factors before multiplying. Once the expression is simplified, carrying out the multiplication becomes just putting those two numerators and two denominators together.
In division, we often talk of multiplying by the reciprocal of the divisor. But in some instances, like our problem, it's easier to spot and eliminate common factors before multiplying. Once the expression is simplified, carrying out the multiplication becomes just putting those two numerators and two denominators together.
- Identify any common factors.
- Cancel the common factors to simplify.
- Perform the multiplication by combining simplified terms.
Other exercises in this chapter
Problem 32
For the following problems, solve the rational equations. $$ \frac{4 a}{a+2}-\frac{3 a}{a-1}=\frac{a^{2}-8 a-4}{a^{2}+a-2} $$
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For the following problems, show that the fractions are equivalent. $$ \frac{-2}{7} \text { and }-\frac{2}{7} $$
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For the following problems, replace \(N\) with the proper quantity. $$ \frac{8 x^{2} y}{5 a^{3}}=\frac{N}{25 a^{3} x^{2}} $$
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For the following problems, add or subtract the rational expressions. $$ \frac{y-1}{y+4}+\frac{y+7}{y+4} $$
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