Problem 32
Question
For the following exercises, use the definition of a logarithm to solve the equation. \(-8 \log _{9} x=16\)
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{1}{81}\).
1Step 1: Isolate the logarithm
First, isolate the logarithmic expression by dividing both sides of the equation by -8:\[-8 \log_{9} x = 16 \]Dividing both sides by -8 yields:\[\log_{9} x = \frac{16}{-8} = -2 \]
2Step 2: Convert from logarithmic form to exponential form
Using the definition of a logarithm, \(\log_b a = c\) is equivalent to \(b^c = a\). In this case, convert \(\log_9 x = -2\) to exponential form:\[9^{-2} = x\]
3Step 3: Evaluate the exponential expression
Calculate \(9^{-2}\):\[9^{-2} = \frac{1}{9^2} = \frac{1}{81}\]So, \(x = \frac{1}{81}\).
Key Concepts
Definition of a LogarithmIsolate the LogarithmConvert Logarithmic to Exponential FormEvaluate Exponential Expressions
Definition of a Logarithm
Logarithms are incredibly useful in mathematics for solving equations involving exponential growth or decay. The definition of a logarithm states that if you have an equation in the form of \( \log_b a = c \), it means that the base \( b \) raised to the power \( c \) will give you \( a \). In simpler terms, the logarithm asks, "To what power must \( b \) be raised, to result in \( a \)?"
This definition helps transform complicated equations into manageable problems. If you can understand 'logarithms', many mathematical puzzles become much easier to solve.
By applying the definition of a logarithm, we can easily switch between logarithmic and exponential expressions, an essential skill when simplifying or solving equations.
This definition helps transform complicated equations into manageable problems. If you can understand 'logarithms', many mathematical puzzles become much easier to solve.
By applying the definition of a logarithm, we can easily switch between logarithmic and exponential expressions, an essential skill when simplifying or solving equations.
Isolate the Logarithm
When you're faced with an equation involving a logarithm, often the first task is to isolate the logarithmic term. This means getting the logarithm on one side of the equation by itself. In our original exercise, we had \( -8 \log_{9} x = 16 \).
To isolate \( \log_{9} x \), divide both sides of the equation by -8:
To isolate \( \log_{9} x \), divide both sides of the equation by -8:
- Divide: \( -8 \log_{9} x \/ -8 = 16 \/ -8 \)
- Simplify: \( \log_{9} x = -2 \)
Convert Logarithmic to Exponential Form
After isolating the logarithm, the next step is to convert it into an exponential form using the definition of a logarithm.
In the exercise, the logarithmic equation was simplified to \( \log_{9} x = -2 \).
According to the definition, this can be converted into an exponential equation:
In the exercise, the logarithmic equation was simplified to \( \log_{9} x = -2 \).
According to the definition, this can be converted into an exponential equation:
- The base is \( 9 \).
- The exponent is \( -2 \).
- Therefore, \( 9^{-2} = x \).
Evaluate Exponential Expressions
Once the equation is in exponential form, the next task is to evaluate the expression to find the solution. In our example, we need to evaluate \( 9^{-2} \).
This can be calculated as follows:
This can be calculated as follows:
- Recognize \( 9^{-2} \) as a fraction: \( \frac{1}{9^2} \).
- Calculate \( 9^2 \), which is \( 81 \).
- Thus, \( 9^{-2} = \frac{1}{81} \).
Other exercises in this chapter
Problem 32
For the following exercises, refer to Table \(8 .\) $$ \begin{array}{|c|c|c|c|c|c|c|} \hline \boldsymbol{x} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \boldsymbol{f}(\bo
View solution Problem 32
For the following exercises, use this scenario: A tumor is injected with 0.5 grams of Iodine-125, which has a decay rate of \(\begin{array}{ll}1.15 \% & \text {
View solution Problem 32
For the following exercises, use properties of logarithms to evaluate without using a calculator. \(2 \log _{9}(3)-4 \log _{9}(3)+\log _{9}\left(\frac{1}{729}\r
View solution Problem 32
For the following exercises, solve for \(x\) by converting the logarithmic equation to exponential form. \(\log _{18}(x)=2\)
View solution