Problem 32
Question
For the following exercises, factor the polynomial. \(121 x^{2}-88 x+16\)
Step-by-Step Solution
Verified Answer
The polynomial factors to \((11x - 4)^2\).
1Step 1: Identify a Pattern
The given polynomial is a trinomial of the form \(ax^2 + bx + c\), where \(a = 121\), \(b = -88\), and \(c = 16\). Notice that 121 is a perfect square (\(11^2\)) and 16 is also a perfect square (\(4^2\)). This suggests that the polynomial might be a perfect square trinomial of the form \((px + q)^2\).
2Step 2: Check for a Perfect Square Trinomial
Assuming the trinomial is a perfect square, the middle term should be twice the product of the square roots of the first and last terms. Calculate \(2 \times 11 \times 4 = 88\). Since the middle term is \(-88x\), which is \(-2 \times 11 \times 4\), the trinomial indeed matches the form of a perfect square trinomial \((px + q)^2 = p^2x^2 + 2pqx + q^2\), so it factors to \((11x - 4)^2\).
3Step 3: Verify the Factorization
Expand \((11x - 4)^2\) to ensure correctness. The expansion yields \((11x - 4)(11x - 4) = 11x(11x) + 11x(-4) + (-4)(11x) + (-4)(-4)\). This simplifies to \(121x^2 - 44x - 44x + 16\), which further simplifies to \(121x^2 - 88x + 16\). The original polynomial and the expanded polynomial are the same, verifying our factorization.
Key Concepts
Perfect Square TrinomialFactoring TechniquesCollege Algebra
Perfect Square Trinomial
A perfect square trinomial is a special type of polynomial that can be expressed as the square of a binomial. When dealing with trinomials like the one in the exercise, which is written as \(ax^2 + bx + c\), identifying a perfect square pattern is the key.
Here are some important points about perfect square trinomials:
Here are some important points about perfect square trinomials:
- The first term \(a\) and the last term \(c\) must be perfect squares. In our exercise, \(121 = 11^2\) and \(16 = 4^2\); both are perfect squares.
- The middle term \(b\) should be twice the product of the square roots of the first and last terms. For example, \(b = -88\) was found to be \(-2 \times 11 \times 4\), matching our perfect square pattern requirement.
Factoring Techniques
Factoring is an essential skill in algebra that allows us to break down complex expressions into simpler, more manageable ones.
The specific technique used in this exercise involves identifying the polynomial as a perfect square trinomial. However, other techniques also exist for factoring polynomials:
The specific technique used in this exercise involves identifying the polynomial as a perfect square trinomial. However, other techniques also exist for factoring polynomials:
- Difference of Squares: Used when a polynomial can be expressed as \(a^2 - b^2 = (a + b)(a - b)\).
- Grouping: Often used in polynomials with four terms, where terms are grouped in pairs to factor out common factors.
- General Trinomial Factoring: Involves factoring polynomials in the form \(ax^2 + bx + c\) by finding two numbers that multiply to \(ac\) and add to \(b\).
College Algebra
College Algebra covers a broad range of topics, building on concepts learned in high school and preparing students for more advanced mathematics.
One crucial aspect of college algebra is mastering polynomial manipulation and factorization. This exercise highlights a fundamental skill that students must develop:
One crucial aspect of college algebra is mastering polynomial manipulation and factorization. This exercise highlights a fundamental skill that students must develop:
- Recognizing special polynomial forms, such as perfect square trinomials, is a skill that simplifies solving polynomial equations.
- In-depth understanding of factoring techniques empowers students to solve equations and inequalities with ease.
- Algebraic proficiency forms the foundation for calculus and other higher-level math subjects, making mastery essential.
Other exercises in this chapter
Problem 31
For the following exercises, solve for the variable. \(4 z-2 z(1+4)-36\) for \(z=5\)
View solution Problem 32
For the following exercises, divide the rational expressions. \(\frac{9 x^{2}+3 x-20}{3 x^{2}-7 x+4} \div \frac{6 x^{2}+4 x-10}{x^{2}-2 x+1}\)
View solution Problem 32
For the following exercises, multiply the binomials. \((9 a-4)(9 a+4)\)
View solution Problem 32
For the following exercises, simplify each expression. \(\sqrt[5]{\frac{-32}{243}}\)
View solution