Problem 32
Question
Find the indicated trigonometric function values. If \(\cot \theta=1,\) and the terminal side of \(\theta\) lies in quadrant \(I,\) find \(\sin \theta\)
Step-by-Step Solution
Verified Answer
\( \sin \theta = \frac{\sqrt{2}}{2} \)
1Step 1: Understand the given information
We are given that the cotangent of an angle \( \theta \) is \( \cot \theta = 1 \) and that \( \theta \) lies in the first quadrant. Our goal is to find \( \sin \theta \).
2Step 2: Use cotangent definition
Recall that \( \cot \theta \) is the reciprocal of \( \tan \theta \), so \( \cot \theta = \frac{1}{\tan \theta} \). Since \( \cot \theta = 1 \), we have \( \tan \theta = 1 \).
3Step 3: Find the reference angle
The equation \( \tan \theta = 1 \) reminds us that in the unit circle this occurs at \( \theta = \frac{\pi}{4} \) radians or \( 45^\circ \) since both sine and cosine of this angle are equal, making the ratio \( \tan \theta = \frac{1}{1} = 1 \).
4Step 4: Determine sine of the angle
Since \( \theta = \frac{\pi}{4} \) (or \( 45^\circ \)) in the first quadrant, we know that \( \sin \theta = \frac{\sqrt{2}}{2} \) because for angle \( \frac{\pi}{4} \), both sine and cosine are equal to \( \frac{\sqrt{2}}{2} \).
5Step 5: Verify first quadrant conditions
In the first quadrant, all trigonometric functions are positive. Since \( \sin \theta = \frac{\sqrt{2}}{2} \) is positive, it confirms that we have the correct value given the condition.
Key Concepts
Quadrant SystemSine FunctionCotangent Function
Quadrant System
The quadrant system is an essential part of understanding trigonometry. It divides the coordinate plane into four distinct sections. Quadrants are designated as I, II, III, and IV, moving counterclockwise from the positive x-axis. Let's delve into some key characteristics of each quadrant:
- Quadrant I: Both x and y coordinates are positive.
- Quadrant II: x is negative, y is positive.
- Quadrant III: Both x and y coordinates are negative.
- Quadrant IV: x is positive, y is negative.
Sine Function
The sine function is a fundamental trigonometric function that associates an angle with the ratio of the opposite side to the hypotenuse in a right-angled triangle. This is often expressed as:\[\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}\]In the context of the unit circle, where the radius is 1, the sine of an angle represents the y-coordinate of a point where the terminal side of the angle intersects the circle.
The sine function varies smoothly between -1 and 1. It is important to note that sine values are positive in Quadrants I and II because the y-coordinates are positive in these quadrants.
The sine function varies smoothly between -1 and 1. It is important to note that sine values are positive in Quadrants I and II because the y-coordinates are positive in these quadrants.
- In Quadrant I: \( \sin \theta > 0 \)
- In Quadrant II: \( \sin \theta > 0 \)
- In Quadrant III: \( \sin \theta < 0 \)
- In Quadrant IV: \( \sin \theta < 0 \)
Cotangent Function
The cotangent function is another important trigonometric function. It is defined as the reciprocal of the tangent function. Mathematically, it is represented as:\[\cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta}\]In a right triangle, it describes the ratio of the length of the adjacent side to the opposite side. Since \( \cot \theta \) is the inverse of \( \tan \theta \), its properties are directly influenced by that of tangent.
- Positive in Quadrants I and III: Where both tangent and cotangent have positive values.
- Negative in Quadrants II and IV: Reflecting tangents negative values.
Other exercises in this chapter
Problem 32
The measures of two sides and an angle are given. Determine whether a triangle (or two) exist, and if so, solve the triangle(s). $$b=16, a=9, \beta=137^{\circ}$
View solution Problem 32
Use a calculator to evaluate the trigonometric functions for the indicated angle values. Round your answers to four decimal places. $$\sin 17.8^{\circ}$$
View solution Problem 32
Convert from radians to degrees. $$\frac{7 \pi}{6}$$
View solution Problem 33
Find the area of each triangle with measures given. $$a=6, b=8, \gamma=80^{\circ}$$
View solution