Problem 32
Question
Find the indicated sum. Use the formula for the sum of the first \(n\) terms of a geometric sequence. $$\sum_{i=1}^{6} 4^{i}$$
Step-by-Step Solution
Verified Answer
The sum of the first 6 terms of the sequence is 5460.
1Step 1: Identifying the Parameters
First identify the first term \(a\), the common ratio \(r\), and the number of terms \(n\). Here, \(a = 4^1 = 4\), \(r = 4\) (since each term is multiplied by 4 to get the next one) and \(n = 6\).
2Step 2: Substitute in the Formula
Next, substitute the values of \(a\), \(r\), and \(n\) into the formula for the sum of the first \(n\) terms of a geometric sequence. You get \(\frac{4(4^6 - 1)}{4-1}\).
3Step 3: Simplify the Terms
Simplify the fraction by doing the calculations. The numerator becomes \(4 \times 4095 = 16380\), and the denominator is \(3\).
4Step 4: Complete the Division
Finally, perform the division to get the sum of the sequence. The result is \(5460\).
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