Problem 32
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus: \(F(5,0)\)
Step-by-Step Solution
Verified Answer
The equation is \( y^2 = 20x \).
1Step 1: Understand the Problem
We need to find the equation of a parabola with its vertex at the origin (0,0) and a focus at (5, 0). The presence of the focus tells us about the direction and properties of the parabola.
2Step 2: Identify the Parabola Type
Since the focus is located on the x-axis (horizontal line), the parabola opens either to the left or right. Given that the x-coordinate of the focus is positive, the parabola opens to the right.
3Step 3: Recall the Standard Equation
For a horizontally opening parabola with vertex at the origin, the standard equation is \[ y^2 = 4px \]where \( p \) is the distance from the vertex to the focus.
4Step 4: Calculate the Parameter p
The distance \( p \) is the x-coordinate of the focus, since the focus is at (5,0) and the vertex is at (0,0). Thus, \( p = 5 \).
5Step 5: Substitute p into the Equation
Substitute \( p = 5 \) into the standard equation: \[ y^2 = 4(5)x \]which simplifies to \[ y^2 = 20x \].
6Step 6: Finalize the Equation
The equation of the parabola with vertex at the origin and focus at (5,0) is\[ y^2 = 20x \].
Key Concepts
VertexFocusStandard Form of Parabola
Vertex
In the world of parabolas, the vertex is a crucial point. It is essentially the "tip" or turning point of the parabola where it makes its sharpest turn. For any parabola, identifying the vertex gives us a firm foundation from which to build an understanding of its shape and position.
- The vertex defines the point at which the parabola changes direction and provides a central anchor for the curve.
- If you imagine a parabola as a bowl, the vertex would be at the very bottom of the bowl (if it opens upwards) or at the top if it's upside down.
- The vertex of a parabola in the standard form equation can usually be found at coordinates \(h, k\).
Focus
The focus of a parabola is not a visible point on its graph like the vertex, but it plays an equally key role. It is intimately related to the parabolic shape, controlling the width and direction.
- Think of the focus as a guiding light for the parabola; the entire curve is constructed in such a way that every point on the parabola is equidistant from the focus and a corresponding line known as the directrix.
- In essence, the focus is one of two fundamental points that define a parabola, the other being the vertex.
- The distance from the vertex to the focus, denoted as \( p \), is a determining factor for the parabola's equation form.
Standard Form of Parabola
The standard form of a parabola is a powerful tool. It simplifies the process of graphing and analyzing these curves by providing a consistent format for the equation.
- For different orientations of parabolas, the standard form will differ slightly to accommodate whether they open upwards, downwards, to the right, or to the left.
- For a parabola opening right or left, as in our exercise, the formula is \((y-h)^2 = 4p(x-k)\). With the vertex at the origin \(h=0\) and \(k=0\), it simplifies to \(y^2 = 4px\).
- Here, \( p \) represents the distance from the vertex to the focus, dictating the direction the parabola opens. This makes \( p \) a centerpiece in writing the actual equation of the parabola.
Other exercises in this chapter
Problem 32
Use a graphing device to graph the ellipse. $$x^{2}+2 y^{2}=8$$
View solution Problem 32
Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find th
View solution Problem 33
Find an equation for the hyperbola that satisfies the given conditions. Foci: \((0, \pm 2),\) vertices: \((0, \pm 1)\)
View solution Problem 33
(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$r=\frac{6}{2+\sin \theta}$$
View solution