Problem 32
Question
Express using positive exponents and simplify, if possible. \(7^{-1}-7^{0}\)
Step-by-Step Solution
Verified Answer
The expression simplifies to \(\frac{-6}{7}\).
1Step 1: Understand Negative Exponent
The expression includes a term with a negative exponent, which is \(7^{-1}\). To express this with a positive exponent, recall that \(a^{-n} = \frac{1}{a^n}\). So, \(7^{-1} = \frac{1}{7}\).
2Step 2: Simplify Zero Exponent
Look at the second term \(7^{0}\). Any non-zero number raised to the power of 0 is 1. So, \(7^{0} = 1\).
3Step 3: Substitute Simplified Terms
Substitute the simplified values back into the expression. The original expression \(7^{-1} - 7^{0}\) becomes \(\frac{1}{7} - 1\).
4Step 4: Common Denominator
To simplify \(\frac{1}{7} - 1\), find a common denominator, which is 7. Rewrite 1 as \(\frac{7}{7}\) so both terms have the same denominator: \(\frac{1}{7} - \frac{7}{7}\).
5Step 5: Subtract Fractions
Subtract the numerators of the fractions while keeping the denominator the same: \(\frac{1}{7} - \frac{7}{7} = \frac{1 - 7}{7} = \frac{-6}{7}\).
Key Concepts
Positive ExponentsZero ExponentFraction Subtraction
Positive Exponents
When working with exponents, moving from negative to positive is crucial for simplification. A positive exponent describes repeated multiplication. For instance, the term \(7^2\) means \(7\) multiplied by itself, which is \(7 \times 7 = 49\). To transform a negative exponent into a positive one, use the rule \(a^{-n} = \frac{1}{a^n}\). This flips the base to the denominator. For example, \(7^{-1}\) becomes \(\frac{1}{7}\). This transition is essential for simplifying expressions and making calculations more intuitive. Remember:
- Positive exponent multiplies the base number repeatedly.
- Negative exponent turns into a reciprocal.
- Use this property to simplify negative exponent expressions.
Zero Exponent
The concept of a zero exponent is straightforward yet powerful. Any non-zero number raised to the zero power always equals one. Mathematically, if \(aeq 0\), then \(a^0 = 1\). This rule applies universally, simplifying many expressions. Even when calculations present complex bases, the zero exponent reduces the result drastically.
For example, in the expression \(7^0\), it's tempting to calculate, but instead, note the result is 1. This property holds for all non-zero bases:
For example, in the expression \(7^0\), it's tempting to calculate, but instead, note the result is 1. This property holds for all non-zero bases:
- \(7^0 = 1\)
- \(10^0 = 1\)
- \(10000^0 = 1\)
Fraction Subtraction
Subtraction of fractions is a fundamental arithmetic operation. It becomes necessary to ensure the fractions have like denominators before subtraction. When subtracting fractions such as \(\frac{1}{7} - 1\), we must first rewrite 1 with a denominator matching the other fraction. Thus, 1 is the same as \(\frac{7}{7}\). With common denominators, the subtraction process involves subtracting numerators while maintaining the denominator.
For the expression becomes:
For the expression becomes:
- Convert \(1\) to \(\frac{7}{7}\), making \(\frac{1}{7} - \frac{7}{7}\).
- Subtract the numerators: \(1 - 7 = -6\).
- The resulting fraction is \(\frac{-6}{7}\).
Other exercises in this chapter
Problem 32
Add the polynomials. $$ \left(\frac{1}{16} r^{6}+\frac{1}{2} r^{3}-\frac{11}{12}\right)+\left(\frac{9}{16} r^{6}+\frac{9}{4} r^{3}+\frac{1}{12}\right) $$
View solution Problem 32
Write number in scientific notation. \(290,000\)
View solution Problem 33
Find each product. See Example 2. $$ \left(0.4-9 m^{2}\right)\left(0.4+9 m^{2}\right) $$
View solution Problem 33
Use the product rule for exponents to simplify each expression. Write the results using exponents. $$ \left(a^{2} b^{3}\right)\left(a^{3} b^{3}\right) $$
View solution