Problem 32
Question
express the distance between the given numbers using absolute value. Then find the distance by evaluating the absolute value expression. 4 and 15
Step-by-Step Solution
Verified Answer
The distance between 4 and 15 is 11.
1Step 1: Identify the two numbers
The two numbers given are 4 and 15.
2Step 2: Calculate the difference
Subtract one number from the other. It doesn't matter which order this is done in because the absolute value will remove any negative sign. 15 - 4 gives 11.
3Step 3: Take the absolute value
The absolute value of 11 is 11. The distance between the numbers 4 and 15 is 11.
Key Concepts
Distance Between NumbersEvaluate Absolute ValueNumber Line
Distance Between Numbers
When we talk about the distance between two numbers, we're really discussing how far apart these numbers are on a number line.
Imagine the number line is like a ruler that stretches from left to right with numbers placed in a sequence.
The concept of distance here is quite simple: It's the total space or gap between the two given numbers. Unlike physical distance, where we account for left or right, on a number line, distance is always positive.
Imagine the number line is like a ruler that stretches from left to right with numbers placed in a sequence.
The concept of distance here is quite simple: It's the total space or gap between the two given numbers. Unlike physical distance, where we account for left or right, on a number line, distance is always positive.
- Think of it like this: If you move from 4 to 15 on the number line, you are covering the space of 11 units.
- Whether you measure from left to right or right to left, the distance remains constant.
Evaluate Absolute Value
Evaluating the absolute value of a number is a simple process that helps in determining the magnitude without considering any negative signs.
In mathematical terms, the absolute value of a number is how far that number is from zero on the number line.
To "evaluate" means to find the value of this expression. Taking the absolute value is straightforward:
This means the distance—as evaluated through absolute value—gives you a clear picture without worrying about direction. Absolute value serves as an essential tool to highlight only the size or scale of the distance.
In mathematical terms, the absolute value of a number is how far that number is from zero on the number line.
To "evaluate" means to find the value of this expression. Taking the absolute value is straightforward:
- If the original number is positive or zero, the absolute value is the same as the original number.
- If the original number is negative, the absolute value is its positive counterpart.
This means the distance—as evaluated through absolute value—gives you a clear picture without worrying about direction. Absolute value serves as an essential tool to highlight only the size or scale of the distance.
Number Line
A number line is a straight line that represents numbers in equal intervals. It acts as a visual aid that can make understanding numbers and their relationships much easier.
By using a number line, you can easily see where numbers are located relative to one another and measure the distance between them.
In our example, you could easily visualize 4 and 15 on the number line, measure the units between them, and confirm that they are 11 units apart, showcasing the distance in an intuitive way. Using a number line for such exercises not only makes the task more visual but also reinforces the core understanding of numerical distance.
By using a number line, you can easily see where numbers are located relative to one another and measure the distance between them.
- Each point on the line corresponds to a single number.
- Moving to the right indicates increasing value, while moving to the left indicates decreasing value.
In our example, you could easily visualize 4 and 15 on the number line, measure the units between them, and confirm that they are 11 units apart, showcasing the distance in an intuitive way. Using a number line for such exercises not only makes the task more visual but also reinforces the core understanding of numerical distance.
Other exercises in this chapter
Problem 31
Multiply or divide as indicated. $$ \frac{x^{2}+x-12}{x^{2}+x-30} \cdot \frac{x^{2}+5 x+6}{x^{2}-2 x-3} \div \frac{x+3}{x^{2}+7 x+6} $$
View solution Problem 32
Simplify each exponential expression $$ \left(x^{11}\right)^{5} $$
View solution Problem 32
Find each product. $$(x+5)(x-5)$$
View solution Problem 32
In Exercises \(31-40,\) factor the difference of two squares. $$x^{2}-144$$
View solution