Problem 32
Question
Exer. 5-40: Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$ y=4 \sin \left(\frac{1}{3} x-\frac{\pi}{3}\right) $$
Step-by-Step Solution
Verified Answer
Amplitude: 4, Period: \(6\pi\), Phase Shift: \(-\pi\).
1Step 1: Identify the Amplitude
The amplitude of a sine function is the absolute value of the coefficient in front of the sine function. Here, the coefficient is 4, so the amplitude is \( |4| = 4 \).
2Step 2: Determine the Period
The period of a sine function is given by the formula \( \frac{2\pi}{b} \), where \( b \) is the coefficient of \( x \) inside the sine function. Here, \( b = \frac{1}{3} \), so the period is \( \frac{2\pi}{\frac{1}{3}} = 6\pi \).
3Step 3: Calculate the Phase Shift
The phase shift is calculated by solving \( \frac{c}{b} \), where \( c \) is the constant term inside the parentheses, and \( b \) is the coefficient of \( x \). Here, \( c = \frac{\pi}{3} \) and \( b = \frac{1}{3} \), so the phase shift is \( -\frac{\pi/3}{1/3} = -\pi \), meaning the graph is shifted to the right by \( \pi \) units.
4Step 4: Sketch the Graph
To sketch the graph, start by drawing the basic sine curve amplified by 4 over one period \( [0, 6\pi] \). Shift this graph to the right by \( \pi \) units to incorporate the phase shift. Mark the key points of the graph where the sine function reaches its maximum, minimum, and zero values in this range.
Key Concepts
AmplitudePeriod of a FunctionPhase ShiftSine Function
Amplitude
Amplitude is one of the fundamental characteristics of a sine function. It measures the maximum extent of the wave from its equilibrium position (middle line) on the graph.
In simpler terms, imagine you are watching the waves at the beach. The amplitude is like the height of a wave from the calm sea level to its peak. For the function given:
In simpler terms, imagine you are watching the waves at the beach. The amplitude is like the height of a wave from the calm sea level to its peak. For the function given:
- The amplitude is determined by the coefficient in front of the sine function. In the equation provided, this coefficient is 4.
- Therefore, the amplitude is simply 4, indicating the highest and lowest points on the graph will be 4 units above and below the center line.
Period of a Function
The period of a function describes how often the function repeats its values. For sine functions, this involves one complete cycle of the wave pattern, from start to finish.
To determine the period of a sine function, one can use the formula:\[Period = \frac{2\pi}{b}\]
To determine the period of a sine function, one can use the formula:\[Period = \frac{2\pi}{b}\]
- Where \( b \) is the coefficient of \( x \) within the trigonometric function.
- In our equation, \( b = \frac{1}{3} \).
- Thus, the period is \( \frac{2\pi}{\frac{1}{3}} = 6\pi \).
Phase Shift
Phase shift refers to the horizontal translation of the graph of a sinusoidal function along the x-axis.
For sine functions, phase shift is calculated by:\[Phase\ Shift = -\frac{c}{b}\]Here:
For sine functions, phase shift is calculated by:\[Phase\ Shift = -\frac{c}{b}\]Here:
- \( c \) is the constant term added or subtracted in the function's argument.
- \( b \) is the coefficient of \( x \) as seen in the sine function.
- In our exercise, \( c = \frac{\pi}{3} \) and \( b = \frac{1}{3} \).
- Thus, the phase shift is \(-\frac{\pi}{3} \cdot \frac{3}{1} = -\pi\).
Sine Function
The sine function is a foundational trigonometric function that creates smooth, periodic wave patterns and is widely used in mathematics.
Its general form is:\[y = a \sin (bx + c)\]Here:
Its general form is:\[y = a \sin (bx + c)\]Here:
- \( a \) is the amplitude, affecting wave height.
- \( b \) determines the period of the wave.
- \( c \) leads to a phase shift.
- A wave that reaches up to 4 units in height and depth.
- Repeats once every \( 6\pi \) units along the x-axis.
- Starts a cycle with a horizontal shift of \( \pi \) to the right.
Other exercises in this chapter
Problem 31
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