Problem 32
Question
Differentiate. $$ f(x)=x^{7} e^{4 x} $$
Step-by-Step Solution
Verified Answer
The derivative is \( f'(x) = e^{4x}(7x^6 + 4x^7) \).
1Step 1: Identify the Rule
The function given is a product of two functions: a polynomial and an exponential function. We will use the product rule for differentiation. The product rule states: if \( u(x) \) and \( v(x) \) are differentiable functions, then \( (uv)' = u'v + uv' \). Let \( u(x) = x^7 \) and \( v(x) = e^{4x} \).
2Step 2: Differentiate \( u(x) = x^7 \)
Differentiate \( u(x) = x^7 \) using the power rule for differentiation: \( \frac{d}{dx}[x^n] = n x^{n-1} \). So \( u'(x) = 7x^{6} \).
3Step 3: Differentiate \( v(x) = e^{4x} \)
The derivative of an exponential function \( e^{ax} \) is \( ae^{ax} \). Therefore, \( v'(x) = 4e^{4x} \).
4Step 4: Apply the Product Rule
Substitute \( u(x), u'(x), v(x), \) and \( v'(x) \) into the product rule formula: \[ f'(x) = u'(x)v(x) + u(x)v'(x) = 7x^{6}e^{4x} + x^{7}(4e^{4x}) \].
5Step 5: Simplify the Expression
Combine like terms in the expression: \[ f'(x) = 7x^{6}e^{4x} + 4x^7e^{4x} \]. Factor out the common term \( e^{4x} \): \[ f'(x) = e^{4x}(7x^{6} + 4x^{7}) \].
Key Concepts
Product RulePower RuleExponential Function Derivative
Product Rule
The product rule is a fundamental concept in calculus used to find the derivative of a product of two functions. In simple terms, it allows us to differentiate functions that are multiplied together. Here's how it works in a nutshell:
- Identify the two functions that are being multiplied. In our example, these are \( u(x) = x^7 \) and \( v(x) = e^{4x} \).
- The product rule states that the derivative of the product \( u(x)v(x) \) is \( (uv)' = u'v + uv' \).
- To apply the rule, differentiate each function separately (find \( u'(x) \) and \( v'(x) \)), then plug them into the formula.
Power Rule
The power rule is one of the simplest and most commonly used rules in differentiation. This rule helps to find the derivative of polynomial functions swiftly.Here's how it works:
- Given a function in the form \( x^n \), the power rule states that its derivative is \( nx^{n-1} \).
- In our exercise, we differentiate \( u(x) = x^7 \). Applying the power rule gives us: \( u'(x) = 7x^{6} \).
- This method can be applied to any polynomial term, making it a quick way to handle derivatives of basic power functions.
Exponential Function Derivative
The derivative of an exponential function is unique because it is proportional to the original function. Here’s a simple way to understand it:
- The derivative of an exponential function \( e^{ax} \) is \( ae^{ax} \), where 'a' is a constant.
- In our example, \( v(x) = e^{4x} \), the derivative is \( v'(x) = 4e^{4x} \).
- This rule highlights a key property of exponential functions: the rate of change of \( e^{ax} \) is always a constant multiple of itself.
Other exercises in this chapter
Problem 31
Given \(\ln 4=1.3863\) and \(\ln 5=1.6094,\) find each value. Do not use a calculator. $$ \ln 80 $$
View solution Problem 32
Retirement planning. Kenna is 30 years old. She plans to retire at age 55 and by then wants to have saved a sum of money that will allow her to withdraw \(\$ 70
View solution Problem 32
Differentiate. $$ y=\log (7 x+3) \cdot 4^{2 x^{4}+8} $$
View solution Problem 32
Given \(\ln 4=1.3863\) and \(\ln 5=1.6094,\) find each value. Do not use a calculator. $$ \ln 20 $$
View solution