Problem 32
Question
Determine the common ratio, the fifth term, and the \(n\)th term of the geometric sequence. $$ 5,5^{c+1}, 5^{2 c+1}, 5^{3 c+1}, \dots $$
Step-by-Step Solution
Verified Answer
Common ratio: 5^c, Fifth term: 5^{4c+1}, nth term: 5^{cn-c+1}.
1Step 1: Understand the First Term
Identify the first term of the sequence. The first term is given as 5, which can be written as \(5^1\).
2Step 2: Identify the Second Term
The second term of the sequence is \(5^{c+1}\).
3Step 3: Calculate the Common Ratio
The common ratio \(r\) in a geometric sequence can be found by dividing the second term by the first term. So, \(r = \frac{5^{c+1}}{5^1} = 5^c\).
4Step 4: Apply the Formula for the Fifth Term
The fifth term of a geometric sequence can be found using the formula \(a_n = a_1 \times r^{n-1}\), where \(n\) is the term position. Substitute the known values: \(a_5 = 5^1 \times (5^c)^{4} = 5 \times 5^{4c} = 5^{4c+1}\).
5Step 5: Derive the General Formula for the nth Term
The nth term can be found using the same formula as above: \(a_n = a_1 \times r^{n-1}\). Here, \(a_n = 5^1 \times (5^c)^{n-1} = 5^{c(n-1)+1}\). Simplifying, we get \(5^{cn-c+1}\).
Key Concepts
Common Rationth Term FormulaFifth Term
Common Ratio
A fundamental component of any geometric sequence is the **common ratio**. It's the factor you multiply by to get from one term to the next. To find the common ratio, divide the second term of the sequence by the first term.
In our exercise, the sequence begins with 5, and the next term is expressed as \( 5^{c+1} \).
The common ratio tells us how the sequence grows, as each term is the previous term multiplied by \( 5^c \). Knowing this ratio is crucial for predicting future terms in the sequence.
In our exercise, the sequence begins with 5, and the next term is expressed as \( 5^{c+1} \).
- First Term: \( 5^1 \)
- Second Term: \( 5^{c+1} \)
The common ratio tells us how the sequence grows, as each term is the previous term multiplied by \( 5^c \). Knowing this ratio is crucial for predicting future terms in the sequence.
nth Term Formula
The **nth term formula** provides a way to calculate any term in the sequence without listing all the terms before it. This shortcut is defined by the formula: \[ a_n = a_1 \times r^{n-1} \]Where:
When we substitute these into the formula, we derive that the nth term \( a_n \) is:\[ a_n = 5^1 \times (5^c)^{n-1} = 5^{cn-c+1} \]This expression allows you to find any term directly, knowing the common ratio and the position of the term in the sequence.
- \( a_n \) is the nth term
- \( a_1 \) is the first term
- \( r \) is the common ratio
- \( n \) is the term number
When we substitute these into the formula, we derive that the nth term \( a_n \) is:\[ a_n = 5^1 \times (5^c)^{n-1} = 5^{cn-c+1} \]This expression allows you to find any term directly, knowing the common ratio and the position of the term in the sequence.
Fifth Term
Calculating specific terms like the **fifth term** in a geometric sequence involves using the nth term formula we discussed. You first identify the position of the term you want, in this case, as the fifth term (\( n = 5 \)).
Here’s how it plays out:
Here’s how it plays out:
- First Term (\( a_1 \)): 5
- Common Ratio (\( r \)): \( 5^c \)
- Term Position (\( n \)): 5
Other exercises in this chapter
Problem 31
Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. \(1,3,5,7, \dots\)
View solution Problem 32
Find the 28 th term in the expansion of \((A-B)^{30}\)
View solution Problem 32
Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. \(1^{2}, 2^{2}, 3^{2}, 4^{2}, \dots\)
View solution Problem 33
The first term of a geometric sequence is \(8,\) and the second term is \(4 .\) Find the fifth term.
View solution