Problem 32
Question
Decide if each function is odd, even, or neither by using the definitions. $$f(x)=x+3$$
Step-by-Step Solution
Verified Answer
The function \(f(x)=x+3\) is neither even nor odd.
1Step 1: Substitute x for -x in the function
First, substitute \(x\) for \(-x\) in the given function. The function becomes \(f(-x) = -x + 3\)
2Step 2: Compare f(x) and f(-x) for even function property
To test if the function is even, you compare \(f(x)\) and \(f(-x)\). If \(f(x) = f(-x)\), then the function is even. In this case, \(f(x) = x + 3\) and \(f(-x) = -x + 3\). It is clear that \(f(x) \neq f(-x)\). Therefore, the function is not even.
3Step 3: Compare f(x) and -f(-x) for odd function property
To test if the function is odd, compare \(f(x)\) and \(-f(-x)\). If \(f(x) = -f(-x)\), then the function is odd. If you replace \(f(-x)\) with \(-f(x)\), get \(-(-x + 3)\) which simplifies to \(x - 3\). It is clear that \(f(x) \neq -f(-x)\). Therefore, the function is not odd.
Key Concepts
Even FunctionOdd FunctionFunction Properties
Even Function
An even function is a type of function with a special symmetry property. When we look at a graph of an even function, it appears mirrored around the y-axis. But how do we mathematically determine if a function is even?
The key is to use the definition: A function is even if, for every input \(x\), the following holds true:
We then compare \(f(x)\) and \(f(-x)\):
The key is to use the definition: A function is even if, for every input \(x\), the following holds true:
- \(f(x) = f(-x)\)
We then compare \(f(x)\) and \(f(-x)\):
- If \(f(x) = f(-x)\), the function is even.
- If not, the function is not even.
Odd Function
Odd functions have their own unique symmetry. This symmetry is around the origin, meaning if you rotate the graph 180 degrees, it looks the same. Mathematically, a function is odd if, for every input \(x\), the relationship is:
Now, compare \(f(x)\) with \(-f(-x)\):
- \(f(x) = -f(-x)\)
Now, compare \(f(x)\) with \(-f(-x)\):
- If \(f(x) = -f(-x)\), the function is odd.
- If not, the function is not odd.
Function Properties
Every function has properties that determine its behavior and characteristics. These properties can include being even, odd, or neither, and are important for understanding a function's graph and its symmetry.
Functions that are neither even nor odd don't exhibit the symmetrical properties we associate with those types of functions. Instead, their symmetry depends on other characteristics or they may not have any apparent symmetry at all.
Let’s reflect on the given function \(f(x) = x + 3\):
Functions that are neither even nor odd don't exhibit the symmetrical properties we associate with those types of functions. Instead, their symmetry depends on other characteristics or they may not have any apparent symmetry at all.
Let’s reflect on the given function \(f(x) = x + 3\):
- We found that it is neither even nor odd, meaning it doesn’t have a y-axis reflection nor an origin symmetry.
- Such functions are quite common and analyzing them requires a look at other features like their monotonicity or discontinuities.
Other exercises in this chapter
Problem 32
In Exercises \(17-40,\) let \(f(x)=-x^{2}+x, g(x)=\frac{2}{x+1},\) and \(h(x)=-2 x+1 .\) Evaluate each of the following. $$(g h)(0)$$
View solution Problem 32
Find a possible expression for a quadratic function \(f(x)\) having the given zeros. There can be more than one correct answer. $$x=0.4 \text { and } x=0.8$$
View solution Problem 33
Solve the inequality algebraically or graphically. $$3 x^{2}-x-1 \geq 0$$
View solution Problem 33
Solve the rational equation. Check your solutions. $$\frac{x-3}{2 x-4}+\frac{1}{x^{2}-4}=\frac{1}{x+2}$$
View solution