Problem 32
Question
CRITICAL THINKING Suppose \(x\) varies inversely with \(y\) and \(y\) varies inversely with \(z\). How does \(x\) vary with \(z\) ? Justify your answer.
Step-by-Step Solution
Verified Answer
In conclusion, if \(x\) varies inversely with \(y\) and \(y\) varies inversely with \(z\), then \(x\) varies directly with \(z\).
1Step 1: Represent the inverse variations
Since \(x\) varies inversely with \(y\), this could be written as \(xy = k_1\), where \(k_1\) is the constant of variation between \(x\) and \(y\). Similarly, since \(y\) varies inversely with \(z\), this can be expressed as \(yz = k_2\), where \(k_2\) represents the constant of variation between \(y\) and \(z\).
2Step 2: Solve for y in inverse relations
Re-arrange the first equation \(xy = k_1\) to solve for \(y\), which yields, \(y = k_1/x\). Similarly, from the equation \(yz = k_2\), solving for \(y\), we get \(y = k_2/z\). The resulting equations help to later substitute and solve for a direct relation between \(x\) and \(z\).
3Step 3: Equate the equations and simplify
Since from both equations, \(y = k_1/x\) and \(y = k_2/z\), \(y\) is a common variable, equate the right hand sides, we have \(k_1/x = k_2/z\). This could be rearranged to the form, \(xz = k_1/k_2\). Thus confirming that \(x\) varies directly with \(z\).
Key Concepts
Direct VariationConstants of VariationMathematical Reasoning
Direct Variation
Direct variation is when two variables change in such a manner that a change in one variable causes a proportional change in the other.
This relationship can be represented by the equation \( y = kx \), where \( k \) is the constant of variation. Essentially, when one variable increases, the other also increases proportionally, and when one decreases, the other does too.
When we talk about direct variation in mathematics, it helps to visualize this as a straight line that passes through the origin if plotted on a graph.
In the context of the exercise, understanding direct variation allowed us to conclude that \( x \) and \( z \) have a linear relationship once the inversions are calculated.
This relationship can be represented by the equation \( y = kx \), where \( k \) is the constant of variation. Essentially, when one variable increases, the other also increases proportionally, and when one decreases, the other does too.
When we talk about direct variation in mathematics, it helps to visualize this as a straight line that passes through the origin if plotted on a graph.
- If \( x \) doubles, \( y \) doubles.
- If \( x \) is halved, \( y \) is also halved.
In the context of the exercise, understanding direct variation allowed us to conclude that \( x \) and \( z \) have a linear relationship once the inversions are calculated.
Constants of Variation
The constant of variation is a key part of both direct and inverse variation.
In an equation that expresses a variation, the constant of variation represents the fixed ratio or product of the variables involved.
In direct variation (like \( y = kx \)), \( k \) represents this constant factor by which one variable multiplies to get the other.
For inverse variation, this constant ensures whatever happens with one variable, an opposite happens with the other. For instance, if \( x \) and \( y \) are inversely related through the equation \( xy = k \), the value of \( k \) remains consistent regardless of the specific values of \( x \) and \( y \) as long as they're inversely related.
In an equation that expresses a variation, the constant of variation represents the fixed ratio or product of the variables involved.
In direct variation (like \( y = kx \)), \( k \) represents this constant factor by which one variable multiplies to get the other.
For inverse variation, this constant ensures whatever happens with one variable, an opposite happens with the other. For instance, if \( x \) and \( y \) are inversely related through the equation \( xy = k \), the value of \( k \) remains consistent regardless of the specific values of \( x \) and \( y \) as long as they're inversely related.
- In the given exercise, the constant \( k_1 \) relates \( x \) and \( y \), while \( k_2 \) relates \( y \) and \( z \).
Mathematical Reasoning
Mathematical reasoning is the process of finding a logical trail from assumptions to consequent conclusions.
This kind of reasoning helps us understand, solve, and even verify mathematical equations and their relationships.
In the original exercise, we utilized reasoning skills to determine how \( x \) and \( z \) relate. By carefully examining the inverse relationships, we equated separate expressions to uncover a direct relationship between \( x \) and \( z \).
With practice, mathematical reasoning becomes intuitive, guiding you through more complex problems with ease and clarity.
This kind of reasoning helps us understand, solve, and even verify mathematical equations and their relationships.
In the original exercise, we utilized reasoning skills to determine how \( x \) and \( z \) relate. By carefully examining the inverse relationships, we equated separate expressions to uncover a direct relationship between \( x \) and \( z \).
- It's about comparing the left and right of the equation.
- It requires connecting dots logically.
With practice, mathematical reasoning becomes intuitive, guiding you through more complex problems with ease and clarity.
Other exercises in this chapter
Problem 31
Find the quotient. $$ \frac{x^2-x-6}{x+4} \div\left(x^2-6 x+9\right) $$
View solution Problem 32
In Exercises 25–32, graph the function. State the domain and range. $$ y=\frac{-2 x+3}{-x+10} $$
View solution Problem 32
Find the quotient. $$ \frac{x^2-5 x-36}{x+2} \div\left(x^2-18 x+81\right) $$
View solution Problem 33
Rewrite the function \(g\) in the form \(g(x)=\frac{a}{x-h}+k\). Graph the function. Describe the graph of \(g\) as a transformation of the graph of \(f(x)=\fra
View solution