Problem 32
Question
Convert the polar equation to rectangular form and sketch its graph. $$ \theta=\frac{5 \pi}{6} $$
Step-by-Step Solution
Verified Answer
The equivalent rectangular equation of \(\theta = \frac{5\pi}{6}\) is a straight line passing through the origin making an angle of \(\frac{5\pi}{6}\) radians with the positive x-axis.
1Step 1: Understand the polar coordinate system
In the polar coordinate system, a point is specified by the radius \(r\) and the angle \(\theta\) formed with the positive x-axis. Based on this understanding, when given \(\theta = \frac{5\pi}{6}\), it informs us that the angle from the positive x-axis is constant and equals \(\frac{5\pi}{6}\).
2Step 2: Convert to rectangular form
The conversion from polar coordinates \((r, \theta)\) to rectangular coordinates \((x, y)\) generally involves applying the equations \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\). However, as our equation only involves \(\theta\), and it is constant, we do not have an equation to convert. Instead, we note that the result of our conversion will be a line of constant \(\theta\).
3Step 3: Sketch the line
The line with \(\theta = \frac{5\pi}{6}\) in the polar coordinate system is a line that includes all points that form an angle of \(\frac{5\pi}{6}\) with the positive x-axis. In other words, we should draw a straight line from the origin making an angle of \(\frac{5\pi}{6}\) radians, or 150 degrees, with the positive x-axis.
Other exercises in this chapter
Problem 32
Sketch the strophoid \(r=\sec \theta-2 \cos \theta,\) \(-\frac{\pi}{2}
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Eliminate the parameter and obtain the standard form of the rectangular equation. $$ \text { Ellipse: } x=h+a \cos \theta, \quad y=k+b \sin \theta $$
View solution Problem 33
In Exercises 33-36, find the length of the curve over the given interval. $$ \begin{array}{ll} \text { Polar Equation } & \text { Interval } \\ \hline r=a & 0 \
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